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1、1. 1. Component representationComponent representation Concentration triangleConcentration triangle Equilateral triangle Clockwise coordinate BCA A%B%C%2. Determine the concentration2. Determine the concentrationB BCA A A%B%C%a). a). To determine composition of point OTo determine composition of poi
2、nt OO Pass point O make a line parallel to BC. Find the intercept from parallel to coordinate A to obtain the contents of constituent A. Similarly, the contents of constituent B,C can be obtained.b). Determine the compositionof alloy I、II、III、IV.A AB BC C908070605040302010102030405060708090102030405
3、06070 8090 A%B%C%IPoint I ：A%=60% B%=30% C%=10%A AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%IIPoint II：A%=20% B%=50% C%=30%b). Determine the compositionof alloy I、II、III、IV.A AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%IIIPoint III ：A%=20% B%=20% C%
4、=60%b). Determine the compositionof alloy I、II、III、IV.A AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%IVPoint IV ：A%=40% B%=0% C%=60%b). Determine the compositionof alloy I、II、III、IV.A AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%c). Point out the alloy
5、c). Point out the alloy possessingpossessing the the composition of composition of 75%A+10%B+75%A+10%B+15%C 15%CA AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%d). Point out the Alloyd). Point out the Alloy possessingpossessing the the composition of composition of 50%A+20%B+5
6、0%A+20%B+30%C 30%CA AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%2. The specific straight line2. The specific straight linein concentration triangle in concentration trianglePoint Point II II : : 20%A- 50%B- 30%CPoint Point III:III: 20%A- 20%B- 60%CPointPoint IV IV : 40%A- 0%
7、B- 60%CIIIIIIVB BC CA A A%B%C%a). The sa). The straight line parallel to a certain edgetraight line parallel to a certain edge PQThe diagonal constituent contains the same concentration. A AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%Draw out the alloy Draw out the alloy poss
8、essing the possessing the composition of composition of A A 40%40%Draw out the Draw out the alloy possessing alloy possessing the composition the composition of C of C 30%30% b). Pass a certain cb). Pass a certain culminationulmination make a straight line make a straight line B BC CA A A%B%C%D Da1
9、a2c2c1a1a2FEConstantConstantA AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%Draw out the alloy Draw out the alloy which iswhich is C / B C / B 1/31/3Draw out Draw out the alloy the alloy which is A / which is A / C C 1/41/43. 3. Linear rule and the center of gravity ruleLinear
10、 rule and the center of gravity rulea). a). Linear ruleLinear rule ApplyApply to two-phase equilibrium to two-phase equilibriumProjected on any side ，calculation with the dual lever law BCA A%B%C% efge f g Rb). b). The center of gravity ruleThe center of gravity ruleBCA A%B%C% efdApply to ternary ph
11、ase equilibriumApply to ternary phase equilibriumR4. 4. Other concentration trianglesOther concentration triangles a). Concentration isosceles trianglesa). Concentration isosceles trianglesConstituent B contains few composition point near to the AC side AC and BCsides are amplified in proportion.ABC
12、b). Concentration right trianglesb). Concentration right trianglesAC% B%The origin is the constituent A substrateOrdinate and abscissa are the constituent B and C respectivelyThe concentration of B and C can be directly read out but A .Constituent A contains massNA AB BC C90807060504030201010203040506070809010203040506070 8090 A%B%C%IV1.Determine the composition o f Alloy I、II、 III、IV. .I II III Exercise
