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1、Restaurant data analysis report15ContentExecutive summary3Introduction3Methods of analysis3Analysis of the each question4Hypothesis14Hypothesis24Hypothesis35Hypothesis46Hypothesis57Hypothesis69Hypothesis710hypothesis811Hypothesis912Hypothesis1013Summary and Recommendations14Reference14Executive summ
2、ary Investigation is undoubted very important for business and personal. The author of this paper think that many elements should be considered to make a better understanding of whether an elegant restaurant will be successfully constructed. In other words, it is necessary to know more information a
3、bout the market. In this report, the software of SPSS will be used to analyze the data and statistical methods will be interpreted in the case.Introduction Michael Jenkins is going to operate his own restaurant and he asked the research film to conduct a survey. The purpose of the survey was to expl
4、ore more information to verify the probability of the success in his restaurant and then giving some useful information to help him make decisions. The report will analyze the market influence factors and use statistical methods such as uni-variate, bi-variate and multi-variate to make the data more
5、 meaningful. At the end, some recommendations based on the analysis result will be given. Methods of analysis Data analysis should be different in different problems(Pallant, 2010). In this the procedure of the data analysis, the approach of the data analysis include as below.The descriptive statist
6、ic is a brief description of the characteristics of the data, such as mean, variance and others.The independent sample T test is one of the uni-variate analyses. This test method is applicable to the assumption of the population whose distribution is normal, population variance is unknown (Larson, 2
7、010). And this test is used to distinguish the difference of the mean between the sample and the population.The paired samples test is one of the bi-variate analyses. The test judged whether two related samples are from the same population and it also assumed that the distribution is normal. Through
8、 comparing the significance of the statistics t of the different samples, the difference between two samples can be seen.The independent test has the same principle as the paired samples. However, it is used when two samples are independent from each other. And the result lies in the significance of
9、 the statistics t.The single factor of variance test is used when the variate is more than two. And it is the foundation of the analysis of variance. The theory of the method is to study the degree of a factor affected by other factors and see whether the results are significant. Pearson correlation
10、 is analyzed to see the simple correlation between two factors and find the potential meaning (Luo, 2011).Analysis of the each questionBecause the sample size is large, so assume that is a normal distribution (Yang. 2011). Hypothesis1. The cost that people desire to pay for a meal is no more than th
11、e calculated value of $19. The null hypothesis is like the subtitle upside. The alternative hypothesis is that the average amount is not less than the forecast value. We use the descriptive statistics and then get the following result as the table 1.Table 1 the average meal to be priced According to
12、 the table, we can see that the mean is 19.23 more than 19, so reject the null hypothesis.Hypothesis2. The average revenue of the people surveyed is different from $70,000.Choose the null hypothesis as the average income is $70,000 and the alternative hypothesis is not equal to $70,000. Because this
13、 is one sample, so the one-sample test is used.Table2 One-Sample TestFrom the table 2 we can see that the statistic value of t is 4.905, the degree of the freedom is 399, the 95% confidence interval is (4247, 9927) and the confidence level of the statistic t is 0.000, so reject the null hypothesis a
14、nd we think the mean of the people surveyed in the revenue is different from $70,000. And the value is $77,087.50 that is significant.Hypothesis3. The preference degree for simple dcor is equal to the degree of elegant dcor. Choose the null hypothesis as the preference for the two samples are the sa
15、me and the alternative hypothesis is the two are not equal. The mean of the two choices for the simple and elegant are 2.26 and 3.64.Because this is the preference related to one person, which means the two samples are related, so the paired sample test is used.Table 3 Paired Samples CorrelationsNCo
16、rrelationSig.Pair 1The Preference for Simple Decor & Elegant Decor400.838.000From the table3 we can see that the statistic value of correlation is o.838, and the confidence level of the correlation test is 0.000, so the two samples have tight relationship with each other.Table 4 Paired Samples TestF
