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十字相乘法练习题(含答案)适合打印

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十字相乘法习题(1)班级 姓名 解:(x+1)(x+17)=0x+1=0或x+17=0∴x1= -1,x2= -17解:(x+1)(x+5)=0x+1=0或x+5=0∴x1= -1,x2= -5解:(x+1)(x+11)=0x+1=0或x+11=0∴x1= -1,x2= -11解:(x+1)(x+2)=0x+1=0或x+2=0∴x1= -1,x2= -2x2 + 3x + 2=0 x2 + 6x + 5=0 x2 + 12x +11=0 x2 + 18x + 17=0 解:(x-1)(x-7)=0x-1=0或x-7=0∴x1= 1,x2= 7解:(x+1)(x-7)=0x+1=0或x-7=0∴x1= -1,x2= 7解:(x-1)(x+7)=0x-1=0或x+7=0∴x1=1,x2= -7解:(x+1)(x+7)=0x+1=0或x+7=0∴x1= -1,x2= -7x2 + 8x + 7=0 x2 + 6x - 7=0 x2 - 6x - 7=0 x2 - 8x + 7=0 解:(x+2)(x-3)=0x+2=0或x-3=0∴x1= -2,x2= 3解:(x-2)(x+3)=0x-2=0或x+3=0∴x1= 2,x2= -3解:(x-2)(x-3)=0x-2=0或x-3=0∴x1= 2,x2= 3解:(x+2)(x+3)=0x+2=0或x+3=0∴x1= -2,x2= -3x2 + 5x + 6=0 x2 - 5x + 6=0 x2 + x - 6=0 x2 - x - 6=0 解:(x-3)(x-5)=0x-3=0或x-5=0∴x1= 3,x2= 5解:(x+3)(x+5)=0x+3=0或x+5=0∴x1= -3,x2= -5解:(x+3)(x-5)=0x+3=0或x-5=0∴x1= -3,x2= 5解:(x-3)(x+5)=0x-3=0或x+5=0∴x1= 3,x2= -5x2 + 2x - 15=0 x2 - 2x - 15=0 x2 + 8x + 15=0 x2 - 8x + 15=0 解:(x+2)(x-11)=0x+2=0或x-11=0∴x1= -2,x2= 11解:(x-2)(x+11)=0x-2=0或x+11=0∴x1= 2,x2= -11解:(x-1)(x-22)=0x-1=0或x-22=0∴x1= 1,x2= 22解:(x+1)(x+22)=0x+1=0或x+22=0∴x1= -1,x2= -22x2 + 23x + 22=0 x2 - 23x + 22=0 x2 + 9x - 22=0 x2 - 9x - 22=0 解:(x-1)(x+22)=0x-1=0或x+22=0∴x1= 1,x2= -22解:(x+1)(x-22)=0x+1=0或x-22=0∴x1= -1,x2= 22解:(x-2)(x-11)=0x-2=0或x-11=0∴x1= 2,x2= 11解:(x+2)(x+11)=0x+2=0或x+11=0∴x1= -2,x2= -11x2 + 13x + 22=0 x2 - 13x + 22=0 x2 - 21x - 22=0 x2 + 21x - 22=0 解:(x+13)(x+13)=0x+13=0或x+13=0∴x1= -13,x2= -13解:(x-13)(x-13)=0x-13=0或x-13=0∴x1= 13,x2= 13解:(x-11)(x-11)=0x-11=0或x-11=0∴x1= 11,x2= 11解:(x+11)(x+11)=0x+11=0或x+11=0∴x1= -11,x2= -11x2 + 22x + 121=0 x2 - 22x + 121=0 x2 - 26x + 169=0 x2 + 26x + 169=0 解:(x+3)(x-4)=0x+3=0或x-4=0∴x1= -3,x2= 4解:(x-3)(x+4)=0x-3=0或x+4=0∴x1= 3,x2= -4解:(x-3)(x-4)=0x-3=0或x-4=0∴x1= 3,x2= 4解:(x+3)(x+4)=0x+3=0或x+4=0∴x1= -3,x2= -4x2 + 7x + 12=0 x2 - 7x + 12=0 x2 + x - 12=0 x2 - x - 12=0 解:(x+1)(x-18)=0x+1=0或x-18=0∴x1= -1,x2= 18解:(x-1)(x+18)=0x-1=0或x+18=0∴x1= 1,x2= -18解:(x-1)(x-18)=0x-1=0或x-18=0∴x1= 1,x2= 18解:(x+1)(x+18)=0x+1=0或x+18=0∴x1= -1,x2= -18x2 + 19x + 18=0 x2 - 19x + 18=0 x2 + 17x - 18=0 x2 - 17x - 18=0 解:(x+3)(x-6)=0x+3=0或x-6=0∴x1= -3,x2= 6解:(x-3)(x+6)=0x-3=0或x+6=0∴x1= 3,x2= -6解:(x-3)(x-6)=0x-3=0或x-6=0∴x1= 3,x2= 6解:(x+3)(x+6)=0x+3=0或x+6=0∴x1= -3,x2= -6x2 + 9x + 18=0 x2 - 9x + 18=0 x2 + 3x - 18=0 x2 - 3x - 18=0 十字相乘法习题(2)班级 姓名 解:(x+2)(x-10)=0x+2=0或x-10=0∴x1= -2,x2= -10解:(x+4)(x+5)=0x+4=0或x+5=0∴x1= -4,x2= -5解:(x+4)(x-5)=0x+4=0或x-5=0∴x1= -4,x2= 5解:(x+2)(x+10)=0x+2=0或x+10=0∴x1= -2,x2= -10x2 + 12x + 20=0 x2 - x - 20=0 x2 + 9x + 20=0 x2 - 8x - 20=0 解:(x+1)(x-20)=0x+1=0或x-20=0∴x1= -1,x2= 20解:(x-1)(x+20)=0x-1=0或x+20=0∴x1= 1,x2= -20解:(x-1)(x-20)=0x-1=0或x-20=0∴x1= 1,x2= 20解:(x+1)(x+20)=0x+1=0或x+20=0∴x1= -1,x2= -20x2 + 21x + 20=0 x2 - 21x + 20=0 x2 + 19x - 20=0 x2 - 19x - 20=0 解:(x+1)(17x+1)=0x+1=0或17x+1=0∴x1= -1,x2= -解:(x+1)(11x+1)=0x+1=0或11x+1=0∴x1= -1,x2= -解:(x+1)(5x+1)=0x+1=0或5x+1=0∴x1= -1,x2= -解:(x+1)(2x+1)=0x+1=0或2x+1=0∴x1= -1,x2= -2x2 + 3x + 1=0 5x2 + 6x + 1=0 11x2 + 12x +1=0 17x2 + 18x + 1=0 解:(x-1)(12x+1)=0x-1=0或12x+1=0∴x1= 1,x2= -解:(x+1)(12x-1)=0x+1=0或12x-1=0∴x1= -1,x2= 解:(x-1)(12x-1)=0x-1=0或12x-1=0∴x1= 1,x2= 解:(x+1)(12x+1)=0x+1=0或12x+1=0∴x1= -1,x2= -12x2 + 13x + 1=0 12x2 - 13x + 1=0 12x2 + 11x - 1=0 12x2 - 11x - 1 =0解:(2x+1)(6x-1)=02x+1=0或6x-1=0∴x1= -,x2= 解:(2x-1)(6x+1)=02x-1=0或6x+1=0∴x1= ,x2= -解:(2x-1)(6x-1)=02x-1=0或6x-1=0∴x1= ,x2= 解:(2x+1)(6x+1)=02x+1=0或6x+1=0∴x1= -,x2= -12x2 + 8x + 1=0 12x2 - 8x + 1=0 12x2 + 4x - 1=0 12x2 - 4x - 1 =0解:(3x-1)(4x+1)=03x-1=0或4x+1=0∴x1= ,x2= -解:(3x+1)(4x-1)=03x+1=0或4x-1=0∴x1= -,x2= 解:(3x-1)(4x-1)=03x-1=0或4x-1=0∴x1= ,x2= 解:(3x+1)(4x+1)=03x+1=0或4x+1=0∴x1= -,x2= -12x2 + 7x + 1=0 12x2 - 7x + 1=0 12x2 + x - 1=0 12x2 - x - 1 =0解:(x-5)(2x+3)=0x-5=0或2x+3=0∴x1= 5,x2= -解:(x+5)(2x-3)=0x+5=0或2x-3=0∴x1= -5,x2= 解:(x-5)(2x-3)=0x-5=0或2x-3=0∴x1= 5,x2= 解:(x+5)(2x+3)=0x+5=0或2x+3=0∴x1= -5,x2= -2x2 + 13x + 15=0 2x2 - 13x + 15=0 2x2 + 7x - 15=0 2x2 - 7x - 15=0 解:(x-3)(2x+5)=0x-3=0或2x+5=0∴x1= 3,x2= -解:(x+3)(2x-5)=0x+3=0或2x-5=0∴x1= -3,x2= 解:(2x-3)(2x+5)=02x-3=0或2x+5=0∴x1=,x2= -解:(x+3)(2x+5)=0x+3=0或2x+5=0∴x1= -3,x2= -2x2 + 11x + 15=0 4x 2+4x- 15=0 2x2 + x - 15=0 2x2 - x - 15=0 解:(5-4x)(4+5x)=05-4x =0或4+5x =0∴x1= ,x2= -解:(3x-1)(6x-5)=03x-1=0或6x-5=0∴x1= ,x2= 解:(2x+5)(4x-7)=02x+5=0或4x。

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