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实例(用 LU 分解和迭代法解线性方程组,用 MATLAB 解题)k=3;A=10 3 1;2 -10 3;1 3 10b=14 -5 14;L=-tril(A,-1)U=-triu(A,1)D=diag(diag(A)B1=D(L+U)f3=norm(B1),f31=max(abs(eig(B1),f1=Db;x=zeros(3,1)for i=1:kx=B1*x+f1end结果为:A =10 3 12 -10 31 3 10b =14-514L =0 0 0-2 0 0-1 -3 0123123014530xxxx 例. 用迭代法解U =0 -3 -10 0 -30 0 0D =10 0 00 -10 00 0 10B1 =0 -0.3000 -0.10000.2000 0 0.3000-0.1000 -0.3000 0f3 =0.4543f31 =0.3873x =000x =1.40000.50001.4000x =1.11001.20001.1100x =0.92901.05500.9290y =2.0893e+004