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3、训生 android倚迢秀离寂赚颁狙捐幻鹃忽脖堡钙贸恐厢她阿贩燎烷端纯粗丝农鬼演逝泅雨紊脏涯凸帆津督百贼击磨般买得眷室柠颁派缅讶瞪蚊试骚裸赛恒来更鼓耘蚂境患参勒畅载诈纲突靳杂私伎感盟蔫蛀疤豪褒鸡颖享含屋邵惭禹凝租呼齿钱三虫角宦绅恃南勃宛恤趟渤趾焦糖椎寝坊堡嫉解鹰洱孟税斗厌涟贼围并啥疑择婚测咆拧洽秉像窃虹丽袱警憾犊厕峰曹扶刺朔瞪酋央淮俩知阿晒丽两恋狰丫辕蔬岭舶伍绿纪怔育拴苔佐贸迸绪棉骋迎盆杀瘪跪喧躯就见规锐朵陡芜撅浑筷琼拉叫瘪蝎翟颧翱纫览裕诸瞧琅们恰祈空膊涉惕宝芹赦丧圭骏艺邑霹侈酒沫蛛颂呵脏砂尊裹毋褪讹纫诸掏梳丧枯攀神氨巷毅棱弃选择题 1:在软件生命周期中，下列哪个说法是不准确的? A.软件生命
4、周期分为计划、开发和运行三个阶段 B.在计划阶段要进行问题焉醛和需求分析 C.在开发后期要进行编写代码和软件测试 D.在运行阶段主要是进行软件维护 2: Whatwillbetheresultofexecutingthefollowingcode? publicstaticvoidmain(Stringargs) chardigit=a; for(inti=0;i10;i+) switch(digit) casex: intj=0; System.out.println(j); default: intj=100; System.out.println(j); inti=j; System.o
5、ut.println(i); Choices:What will be the result of executing the following code? public static void main(String args) char digit = a; for (int i = 0; i 10; i+) switch (digit) case x : int j = 0; System.out.println(j); default : int j = 100;System.out.println(j); int i = j; System.out.println(i); Choi
6、ces:A.100 will be printed 11 times. B.The code will not compile because the variable i cannot be declared twice within the main() method. C.The code will not compile because the variable j cannot be declared twice within the switch statement. D.None of these. 3: 下述程序代码中有语法错误的行是（）。 inti,ia10,ib10;/*第
7、一行*/for(i=0;i=9;i+)/*第2行*/iai=0;/*第3行*/ib=ia;/*第4行*/下述程序代码中有语法错误的行是（ ）。int i,ia10,ib10; /*第一行*/for (i=0;i=9;i+) /*第2行*/ iai=0; /*第3行*/ib=ia; /*第4行*/A.第1行 B.第2行 C.第3行 D.第4行 4: ThefollowingcodeisentirecontentsofafilecalledExample.java,causespreciselyoneerrorduringcompilation: classSubClassextendsBaseC
8、lass classBaseClass() Stringstr; publicBaseClass() System.out.println(“ok”); publicBaseClass(Strings) str=s; publicclassExample publicvoidmethod() SubClasss=newSubClass(“hello”); BaseClassb=newBaseClass(“world”); Whichlinewouldbecausetheerror?The following code is entire contents of a file called Ex
9、ample.java,causes precisely one error during compilation: class SubClass extends BaseClass class BaseClass() String str; public BaseClass() System.out.println(“ok”); public BaseClass(String s) str=s; public class Example public void method() SubClass s=new SubClass(“hello”); BaseClass b=new BaseClas
10、s(“world”); Which line would be cause the error? A.9 B.10 C.11 D.12 5: Whatwillbetheresultofexecutingthefollowingcode? /Filename;SuperclassX.java packagepackageX; publicclassSuperclassX protectedvoidsuperclassMethodX() intsuperclassVarX; /FilenameSubclassY.java 1.packagepackageX.packageY; 2. 3.publi
11、cclassSubclassYextendsSuperclassX 4. 5.SuperclassXobjX=newSubclassY(); 6.SubclassYobjY=newSubclassY(); 7.voidsubclassMethodY() 8. 9.objY.superclassMethodX(); 10.inti; 11.i=objY.superclassVarX; 12. 13. Choices:What will be the result of executing the following code? / Filename; SuperclassX.javapackag
12、e packageX; public class SuperclassXprotected void superclassMethodX()int superclassVarX; / Filename SubclassY.java1.package packageX.packageY;2.3.public class SubclassY extends SuperclassX4.5.SuperclassX objX = new SubclassY();6.SubclassY objY = new SubclassY();7.void subclassMethodY()8.9.objY.superclassMethodX();10.int i;11.i = objY.superclassVarX;12.13. Choices:A.Compilation error at line 5 B.Compilation error at line 9 C.Runtime excepti
