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1、电路分析基本各章习题参照答案第1章 习题参照答案1-1 (1) 50W;(2)300 V、25,200V、75 V;()21.5,R30,R4=7.5- VA=85V,m=5,VB=0.V,C12V,VD=19V,Vp=215V,UA=8V,U=12.5,UDA27. 1- 电源(产生功率):A、B元件;负载(吸取功率):、D元件;电路满足功率平衡条件。1-4 () VA=100V,V=9V,VC97V,VD=,VV,VF=1V,AF9V,UCE=92V,BE94V,UBF9V,A=3 V;() VC9,VB9V,VA=93V,V=2V,F=6,VG=V,UAF=99V,CE=92V,UB9V
2、,UBF=8V,UCA=3 V1 0.18A , 6度,2.7元16 I=A, 1=11A,I2=117 (a) =V,(b)U=24 V,() R=5,(d)I23A-8 (1) i6=1A; (2) u4=10V,u6=3 ;(3) P1=2W发出,P2=6W吸取,P3=1吸取,=1发出,P7W发出,P=3发出1-9 I1,US134V,R7.81-10S断开:UAB=.8,UAO=12,BO7.2V;S闭合:UABV,12V,UB=0V1-1 支路3,节点2,网孔,回路3112 节点电流方程:(A)I1 +II6=0,(B)I6I5I,(C)5 4I回路电压方程:I6 6+ U5 IR5
3、US3 +I3 R3=0,5 R5+ I7R7US4=0,I3 R3+ US3 + US4 + I1 R2+1 R1 013 UAB=1,I2=0.A,3=.5A, R32.1-4 A0,VC=10V,VD90V,AC=80V,UAD=30V,U=50V1- I12A,I=3,35A,I4=7A,I5=2A第2章 习题参照答案2-1 2.4 ,A2-2 (1) 4 V,2 ,1 V;(2) 40 A,0mA,10mA231.5,2,1/2-4 6 , 25 2 A,1 2- 1 A7 2 2-8 1 A-9 I1 14A,I2 = 1.6 A,I3= 0. A2-1 1 = ,2 = A,P
4、=0 ,P2= 18 W2-11 I1 = 1 mA,I = 2,E = V2-12 I1 =6 A,I2 = 3 A,I = 3 A2-1 = A,2 = A,I 1A,I4=,I5 = 1 2-14 a 2 V , 1 A,I2 =2 A2-5 Va = 6,I1 .5 A,I2=1A,I3 = 0. A2-1 Va = 1 V,I1= 1 A,I2 ,I3 =3 A2-17 I1 = A,I2 2- I1 = .5 ,IA,I3 = 0.5 A219 I1 = 0.8 A,I =0.7A,I3= 2 A,4= 2.75 A,I =1.552-20 I 5A-2 U0=2 V,R0= 4
5、,I =01 2-2 = 1 A2-23 () I= 0A,Uab ;()I5 = A,Ua = 11 24 IL = 2 25 IS =1 A,0 2 -2 18 ,2 ,1227 U5-2 I =1 A2-9 U=5 30 I = A-31 10 V,180 2-32U =9V,0 =6 ,U5 V第3章习题参照答案3- 50,314rds,0s,141V,00,12032 200V,141.V3-3 u=14.1sin (314t60) V3-4 (1) 210;(2) 90,221,1u=20(不变)3 (1) ,;(2) u3100s (t4)V,u410i (13)V- (1)i1
6、=14.1 n (72)A;(2) u2=300 i (t60)V3-7 错误:() ,(3),(4),()3- (1) R;() L;() C;(4) R3-9 i=2.2 sn (t3)A,Q4var31 u=4.9n (34t135) V,=3.18 var3-11 ()=0;(2) P.kW3-2 (1)1.4A,;(3)Q38 var,P=0W;(4) i0.98 n (680) A33 (1)=9.7A,i.7sin (314t+15) A;()Q=127.4 var,P=W;(4)IC=03-14 ()C20.3F;() IL0.25A,IC16A第章 习题参照答案4-1 ()
7、,;() ,4- Y=(06-.0) S,R1.6 ,XL=.,L0.0 H ,4-4 45 ,,,,-6 ,,4-7 ,4- ()30 V;(b) .2 4- (a) 1 V;(b) 10 4-10 ()V;() 10 V4-1 U=4.1 V412 UL1 15V,C2 =8V,US1.6 V-1 UX1 =00 V,=600,X1=1 ,X220 ,3= 4-14 ,,,,-5 (1),,;(),4-16P 774 ,Q 58. ar,S = 96A4-17 I1= 5,I 4 4-8 I = 1 A,I= 2 A,,4-19 ,4-20 0 6 ad/s, =100 , = 100,I
8、 2 ,R =20 mV,UL = C = 2 V421 0=04 rad, = 10,Q= 10,U = 10 V,IR = mA,IIC 100 mA4- L = 1 H, 03H第5章 习题参照答案5-3 M =5.5 H4 01 =100 rad/,2=226rad/-5 Z1= j.4,= j6. 5- Z =37.5 5-7 130m5-8 5 1 4.8 V5-10 M12 2 mH,I1= A511 U2 220 V,I1= 4 A- = 19 513 N2= 254匝,3 = 72匝5-14 n ,P2= 31.5 mW第6章 习题参照答案6-1 ()A相灯泡电压为零,B、C
9、相各位为V63 IL Ip =4.4,p =22V, = 380 ,P= 2.3kW6- (2) Ip=7.62 ,I 13.2 6-5 、相各为22,B相为8A66 UL 404V6- V6- cs = 0.961,Q= .75 kvr6-9 10 (1) Ip =11.26 , 1.34.3 ; (2) Ip = Il = 11.26A,P = k-1 l = 91V6-1 6-13 UV = 16 6-14() 负载以三角形方式接入三相电源(2) ,,,6-5 L = 110H,C 91.9 mF第7章 习题参照答案7- P =24 W, = 60var72 P 104-3 (1) (2
10、) I3.4 A ,58.4V,93.0 4 ,-5 直流电源中有交流,交流电源中无直流76 U153 ,=,L= 11.4 m;约为%,(L 12.33 mH)-7 使总阻抗或总导纳为实数(虚部为0)的条件为78 ,7-9 L 1H,L2 =66.7 m7 1= 1 F,C2 .25 F第8章 习题参照答案8-6 iL(0+)=15,u()1V-7 i1(0+)4A,i2(0+)1A,uL(0)2,1()=3,i2()=0,uL()08- i1(0+)=75mA,i2(0+)=75m,i(0+),uL1(0)=0,uL(0+)25V89 10 8-11 ,*812 -13 ,8-4 ,8-1 () .1,(2) ,(3) t=0.1s-16 8-1 -1();(b)81 8-2 uo为三角波,峰值为.5V8-21 临界阻尼R= ,欠阻尼R2*8-22