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1、自动化翻译岗位职责第1篇：自动化岗位职责 自动化操作岗位职责 1.严格遵守、仔细实行公司各项方针政策和规章制度。 2.坚守岗位、遵守劳动纪律。严禁离岗、串岗、睡岗，不做与工作无关的事。 3.严格根据工艺要求及操作规程进行操作。 4.在操作过程中，严格执行工艺指标：缓冲罐压力101KPa，氯化釜温度52。 5.仔细遵守考勤制度，按时上下班。有事提前请假。 6.加强巡回检查，特殊是空气站，每班排污一次，留意空气压力是否正常（0.4-0.6MPa）,如有异样刚好通报。 7.亲密关注气体系统的报警状况，严禁关闭报警声音，如有报警产生刚好通报。 8.时刻关凝视频监控系统，如有异样状况刚好通报。 9.按规
2、定填写当班各项相关记录，严格执行交接班制度。 第2篇：自动化翻译 第一部分：原文 The Operational Amplifier One problem with electronic devices corresponding to the generalized amplifier is that the gains, Au or AI, depend upon internal properties of the two-port system（, , RI, Ro, etc.).This makes design difficult since these parameters u
3、sually vary from device to device, as well as with temperature.The operational amplifier, or Op-Amp，is designed to minimize this dependence and to maximize the ease of design.An Op-Amp is an integrated circuit that has many component part such as resistors and transistors built into the devices.At t
4、his point we will make no attempt to describe these inner working. A totally general analysis of the Op-Amp is beyond the scope of some texts.We will instead study one example in detail, then present the two Op-Amp laws and show how they can be used for analysis in many practical circuit application
5、s.These two principles allow one to design many circuits without a detailed understanding of the device physics.Hence, Op-Amps are quit useful for researchers in a variety of technical field who need to build simple amplifiers but do not want to design at the transistor level.In the texts of electri
6、cal circuits and electronics they will also show how to build simple filter circuits using Op-Amps.The transistor amplifiers, which are the building blocks form which Op-Amp integrated circuits are constructed, will be discued. The symbol used for an idea Op-Amp is shown in Fig.1-2A-1. Only three co
7、nnections are shown: the positive and negative inputs, and the output.Not shown are other connections neceary to run the Op-Amp such as its attachments to power supplies and to ground potential.The latter connections are neceary to use the Op-Amp in a practical circuit but are not neceary when consi
8、dering the ideal Op-Amp applications we study in this unit.The voltages at the two inputs and the output will be represented by the symbols , and .Each is measured with respect to ground potential.Operational amplifiers are differential devices.By this we mean that the output voltage with respect to
9、 ground is given by the expreion = A (- ) (1-2A-1) Where A is the gain of the Op-Amp and and the voltages at inputs.In other words, the output voltage is A time the difference in potential between the two inputs. Integrated circuit technology allows constructions of many amplifier circuits on a sing
10、le composite “chip” of semiconductor material.One key to the succe of an operational amplifier is the “cascading” of number of transistor amplifiers to create a very large total gain.That is, the number A in Ep.(1-2A-1) can be on the order of 101,000 or more.(For example, cascading of five transisto
11、r amplifiers, each with a gain of 10, would yield this value for A.) A second important factor is that these circuit can be built in such a way that the current flow into each of the inputs is very small.A third important design feature is that the output resistance of the operational amplifier () i
12、s very small.This in turn means that the outpt of the device acts like an ideal voltage source. We now can analyze the particular amplifier circuit given in Fig.1-2A-2 using these characteristics.First, we note that the voltage at the positive input, = .Various currents are defined in part b of the
13、figure.Applying KVL around the outer loop in Fig.1-2A-2band remembering that the output voltage, , is measured with respect to ground, we have -=0 (1-2A-2) Since the Op-Amp is constructed in such a way that no current flows into either the positive or negative input, = 0.Applying KCL at the negative
14、 input terminal then yields = Using Ep.(1-2A-3) and setting ， I We may use Ohms law to find the voltage at the negative input, , nothing the aumed current direction and the fact that ground potential is zero volts: = I So, and form Ep.(1 -2A-3) =() Since we now have expreions for , Eq.(1-2A-1) may b
15、e used to calculate the output voltage, Gathering terms, (1-2A-4) And finally, (1-2A-5a) This is the gain factor for the circuit.If A is a very large number, large enough that A (), the denominator of this fraction is dominated by the A term.The factor A, which is in both the numerator and denominator, then cancels out and the gain is given by the expreion (1-2A-5b) This shows that if A is very large, then the gain of the circuit is independent of the exact value of A and can be controlled by the choice of .This is one of the key features of Op-Amp designthe action of the circuit on signal
