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1、C 语言复习题_指针&结构体一、选择1、若有以下定义：char s20=programming,*ps=s; 则不能代表字符 o的表达式是 A。A) ps+2 B) s2 C) ps2 D) ps+=2,*ps2、若有以下定义和语句: int a10=1,2,3,4,5,6,7,8,9,10,*p=a;则不能表示 a 数组元素的表达式是 B。 A) *p B) a10 C) *a D) ap-a3、已知 int *p,a; p= 这里的运算符 & 的含义 D。A) 位与运算 B) 逻辑与运算 C) 取指针内容 D) 取变量地址4、定义结构体如下：struct student int num;c
2、har name4;int age; 则 printf(“%d”,sizeof(struct student)的结果为: 12。5、若有定义如下:int i=3,*p= 显示 i 的值的正确语句是 B。A) printf(“%d”,p);B) printf(“%d”,*p);C) printf(“%p”,*p);D) printf(“%p”,p);6、在定义结构体时，下列叙述正确的是 A。A) 系统不会分配空间B) 系统会按成员大小分配空间C) 系统会按最大成员大小分配空间D) 以上说法均不正确7、指针是一种 D。A) 标识符B) 变量C) 运算符D) 内存地址8、定义 struct s in
3、t x; char y6; s1;,请问正确的赋值是 C。A) s1.y=”abc”;B) s1-y=”abc”;C) strcpy(s1.y,”abc”);D) s1.strcpy(y,”abc”);9、已知定义“int x 1, *p”，则合法的赋值表达式是 A。A) p &x B) p = x C) *p &x D) *p *x10、在 C 语句中，&后跟指针变量名，表示该指针变量的 C。A) 值 B) 别名 C) 地址 D) 类型二、程序填空1、下面程序的功能是实现数组元素中值的逆序。#include void invert(int *s, int num);int main( ) i
4、nt i, n=5, a5=1,2,3,4,5;1 ; /调用函数逆序for(i=0;istruct TIMEint hour, minute, second;void InputTime(struct TIME *p)scanf(%d : %d : %d, void OutputTime(struct TIME p)printf(%02d:%02d:%02d, p.hour, p.minute, p.second);int Sub(struct TIME x, struct TIME y)int t1 = x.hour * 3600 + x.minute * 60 + x.second;in
5、t t2 = y.hour * 3600 + y.minute * 60 + y.second;return t1 - t2;int main()struct TIME a, b;int r;printf(a = ? ); InputTime(printf(b = ? ); InputTime(r = Sub(b, a);printf(a = ); OutputTime(a); putchar(n);printf(b = ); OutputTime(b); putchar(n);printf(r = %dn, r);return 0;答：a = ? 7:59:59 b = ? 8:10:02
6、a = 07:59:59 b = 08:10:02 r = 603 2、#include #include string.h int main ( )int i,n;char *s=abcdef123;n=strlen(s);for (i=n-1;i=0;i-)printf(%c,*(s+i);return 0;答：321fedcba3、#includevoid Fun(int *y);int main ( )int x = 10;printf(x = %dn, x);Fun(printf(x = %dn, x);return 0;void Fun(int *y) printf(*y = %d
7、n, *y);*y = 20; printf(*y = %dn, *y); 答：x=10*Y=10*Y=20X=204、仔细阅读下面的程序, 当复数 a 为 3+4i, b 为 5+8i 时, 请写出程序的输入和输出结果。#include #include struct COMPLEXdouble re, im;void InputComplex(struct COMPLEX *p)scanf(%lg %lg, void OutputCoord(struct COMPLEX p)printf(%lg%+lgi, p.re, p.im);struct COMPLEX Add(struct COM
8、PLEX p, struct COMPLEX q)struct COMPLEX r;r.re = p.re + q.re; r.im = p.im + q.im;return r;int main()struct COMPLEX a, b, c;printf(a = ? ); InputComplex(printf(b = ? ); InputComplex(c = Add(a, b);printf(a = ); OutputCoord(a); putchar(n);printf(b = ); OutputCoord(b); putchar(n);printf(c = ); OutputCoo
9、rd(c); putchar(n);return 0;答：a = ? 3 4 b = ? 5 8 a = 3+4i b = 5+8i c = 8+12i 5、#include struct date int year; int month; int day;void func(struct date *p) p-year = 2000;p-month = 5;p-day = 22; int main() struct date d;d.year = 1999; d.month = 4; d.day = 23;printf(%d,%d,%dn,d.year, d.month, d.day);fu
10、nc( printf(%d,%d,%dn,d.year, d.month, d.day);return 0;答：1999,4,232000,5,22五、程序设计1、编写程序, 输入一组正实数, 按降序从大到小排序, 然后输出。例如: (虚线部分为用户输入的内容)n = ? 96.9 2.5 3.8 7.1 1.6 4.3 8.2 5.4 9.79.7 8.2 7.1 6.9 5.4 4.3 3.8 2.5 1.6要求: 编写下面三个函数 , 分别完成输入、排序和输出的功能 , 并编写主函数, 完成整个程序(可以增加一些辅助函数)。void InputArray(double *p, int n
11、);void OutputArray(const double *p, int n);void SortArray(double *p, int n);#include void InputArray(double *p, int n);void OutputArray(const double *p, int n);void SortArray(double *p, int n);void Swap(double *x, double *y);int main()double a100;int n;printf(n = ? );scanf(%d, InputArray(a, n);void
12、OutputArray(const double *p, int n)int k;for (k = 0; k 0; i -)for (j = 0; j void InputArray(double *p, int n);double MaxArray(double *p, int n);double SumArray(double *p, int n);int main()double a100;int n;printf(n = ? );scanf(%d, InputArray(a, n);double MaxArray(double *p, int n)int k;double max = p0;for (k = 1; k max)max = pk;return max;printf(最大值 = %lgn, MaxArray(a, n);printf(总 和 = %lgn, SumArray(a, n);return 0;void InputArray(double *p, int n)int k;for (k = 0; k n; k +)scanf(%lg, double SumArray(double *p, int n)int k;double sum = 0;for (k = 0; k n; k +)sum += pk;return sum;
