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1、部分习题答案xy01AE,0C,1BB,0A,0CA,1E,0DA,1B,0EC,0D,14.3 xy01AA,0C,0BA,0A,0CD,1A,0DC,1B,0 (a) (b) x1x2 y00011110AB,0B,0B,1A,0BA,0B,0B,1C,1CB,0C,0A,1B,0 (c)4.4 (2,3,5)、(2,5,6)、(1,3)、(1,4)、(1,6)4.5 x1x2 y00011110AA,0A,1C,dA,dBC,1A,0d,dA,dCB,dC,dA,dC,d (a)xy01Ad,0C,dBA,1D,1CA,1B,1DD,dA,dxy01AA,1B,1BB,0A,0 (c)
2、(b)4.6 仅给出状态表如下:xy01AA,0B,0BC,0B,0CA,0B,14.7 仅给出激励和输出函数: , ,4.8 状态表如下:xy01q0q0,0q1,1q1q0,1q1,04.9状态表如下:xy01q1q4,1q2,1q2q4,1q1,1q3q4,1q3,1q4q4,1q1,0 00 01 11 104.10 状态图如下: 000 001 011 100 110 111 010 101 4.11状态表如下:xy2y101q1q1,0q2,0q2q2,0q3,0q3q3,0q4,0q4q4,0q1,1 00 01 10 114.12状态表如下: y1y2y3y4000111100
3、0000111001101dddd01001101000000dddd1100100101dddddddd1001100111dddddddd4.13 激励和输出函数为: , , T31 4.14 提示:可用模8计数器实现。4.15状态表如下: c1c2y00011110AB,0C,0D,1B,0BC,0A,0A,0C,0CA,1B,0B,0D,0Dd,dd,dC,0A,14.16状态表如下:xy01AB,1B,1BB,1C,1CC,1D,0DC,1A,14.17状态表如下:xy2y1010011,001,00100,110,01001,011,11110,000,04.18 提示:可参考串行
4、BCD码校验器的设计方法画出状态图。5.1状态表如下: x1x2y0001111011,11,11,11,122,11,14,13,133,11,11,01,044,11,12,13,1 x1x2y00011110A,0,0B,dC,dBC,1,1,1C,1C,1A,d,d,1DA,0A,0,0,05.2 x1x2y000111101,05,0d2,d28,1d8,d,13d5,0,04,041,0d3,0,051,0,06,dd 6d7,1,12,178,1,16,1d8,15,dd2,1 (a)原始流程表 (b)简化流程表5.3 RS异步触发器流程表: RSy1y2000111100011
5、10010100001100000000101000005.4 简化流程表: x1x2y00011110A,0B,0D,0,0B,0,0D,0C,dCA,ddD,d,1DB,0,0,0,05.5 次态函数和输出函数为: 或 5.7 流程表如下: x1x2y1y2000111100000,101,111,010,00111,001,011,010,01111,001,011,010,01000,110,111,010,0次态和输出响应序列为:x1 0 0 1 1 0 0 0 1x2 0 1 1 0 0 1 0 0Y1 0 0 1 1 0 0 1 1Y2 0 1 1 0 0 1 1 0Z 1 0 0 0 1 0 0 0