《无线通信原理与应用第三章PPT课件》由会员分享，可在线阅读，更多相关《无线通信原理与应用第三章PPT课件（36页珍藏版）》请在金锄头文库上搜索。
1、Chapter 3:Mobile Radio Propagation:Large-Scale Path Loss8/2/20241 3.1 Introduction to Radio wave Propagation Small-scale and large-scale fading8/2/202423.2 Free Space Propagation ModelIn free space, the received power is predicted by Firiis Equ.Pr(d):ReceivedpowerwithadistancedbetweenTxandRxPt:Trans
2、mittedpowerGt:TransmittingantennagainGr:Receiveantennagain:Thewavelengthinmeters.d:distanceinmetersL:ThemiscellaneouslossesL(L=1)areusuallyduetotransmissionlineattenuation,filterlosses,andantennalossesinthecommunicationsystem.L=1indicatesnolossinthesystemhardware.8/2/20243Reflection: occur from the
3、surface of the earth and from buildings and walls.Diffraction:occurs when the radio path between the transmitter and receiver is obstructed by a surface that has sharp irregularities (edges).Scattering:occurs when the medium through which the wave travels consists of objects with dimensions that are
4、 small compared to the wavelength, and where the number of obstacles per unit volume is large. 3.3 The three Basic Propagation Mechanisms8/2/20244reflection（反射）atlargeobstacles,Scattering(散射)atsmallobstacles,diffraction(衍射)atedges8/2/20245EIRP&ERPEIRP:EffectiveIsotropicRadiatedPowerRepresentsthemaxi
5、mumradiatedpoweravailablefromatransmitterinthedirectionofmaximumantennagain,ascomparedtoanisotropicradiator.ERP:EffectiveRadiatedPowerERPisusedinsteadofEIRPtodenotethemaximumradiatedpowerascomparedtoahalf-wavedipoleantenna(insteadofanisotropicantenna).Inpractice,antennagainsaregiveninunitsofdBi(dBga
6、inwithrespecttoanisotropicsourse)ordBd(dBgainwithrespecttoahalf-wavedipole)2.15dB8/2/202469dBiantenna&3dBiantenna8/2/20247PathLossThepathloss,whichrepresentssignalattenuationasapositivedifference(indB)betweentheeffectivetransmittedpowerandthereceivedpower.Thepathlossforthefreespacemodelwhenantennaga
7、insareincludedisgivenbyquantitymeasuredindB,isdefinedastheWhenantennagainsareexcluded,theantennasareassumedtohaveunitygain,andpathlossisgivenby(f:MHz,d:km)8/2/20248TheFriisfreespacemodelisonlyavalidpredictorforPrforvaluesofd,whichareinthefar-fieldofthetransmittingantenna.Thefar-fieldofatransmittinga
8、ntennaisdefinedastheregionbeyondthefar-fielddistancedf,whichisrelatedtothelargestlineardimensionofthetransmitterantennaapertureandthecarrierwavelength.Thefar-fielddistanceisgivenbyTobeinthefar-fieldregion,dmustsatisfyThefar-fieldregionofatransmittingantenna8/2/20249The Reference DistanceItiscleartha
9、tequationdoesnotholdford=0.Forthisreason,large-scalepropagationmodelsuseaknownreceivedpowerreferencepoint.Thereceivedpower,Pr(d),atanydistancedd0,mayberelatedtoPratd0.IfPrisinunitsofdBmordBW,thereceivedpowerisgivenby8/2/2024103.4LinkbudgedesignusingpathlossmodelLog-distancepathlossmodelBoth theoreti
10、cal and measurement-based propagation models indicate that average received signal power decreases logarithmically with distance, whether in outdoor or indoor channels. The average large-scale path loss for an arbitrary T-R separation is expressed as a function of distance by using path loss exponen
11、t n.n is the path loss exponent which indicates the rate at which the path loss increases with distanced0 is the close-in reference distance which is determined d is the T-R separation distance8/2/202411Path-lossexponents8/2/202412If a transmitter produces power:Pt=50w, receive sensitivity (minimum
12、usable signal level)is -100dbm.Assume d0=100m, with a 900MHz carrier frequency, n=4,Gt=Gr=1; find the coverage distance d.Transmit Power: Pt=50W=47dBmPr(d0)=-24.5dBmPL(dB)=40log(d/d0)=-24.5-(-100)=75.5dbIf n=4,log(d/d0)=75.5/40=1.8875,d=7718mExample18/2/202413ThemodelinEquation(3.11)doesnotconsidert
13、hefactthatthesurroundingenvironmentalcluttermaybevastlydifferentattwodifferentlocationshavingthesameT-Rseparation.Thisleadstomeasuredsignalswhicharevastlydifferentthantheaverage valuepredictedbyEquation(3.11).Log-normalShadowing8/2/202414Log-normal Shadowing 8/2/202415Determination of Percentage of
14、Coverage Area8/2/202416U(r)asafunctionofprobabilityofsignalabovethresholdonthecellboundary.8/2/202417Example2Alocalaveragesignalstrengthfieldmeasurements,themeasureddatafitadistant-dependentmeanpowerlawmodelhavingalog-normaldistributionaboutthemean.Assumethemeanpowerlawwasfoundtobe.Ifasignalof1mWwas
15、receivedatd0=1mfromthetransmitter,andatadistanceof10m,10%ofthemeasurementswerestrongerthan-25dBm,definethestandarddeviation,forthepathlossmodelatd=10m.8/2/202418Fourreceivedpowermeasurementsweretakenatdistancesof100m,200m,1km, and 3 km froma transmitter. These measuredvalues are given in thefollowin
16、gtable.ItisassumedthatthepathlossforthesemeasurementsfollowsthemodelinEquation(3.12.a),whered0 = 100m:(a)findtheminimummeansquareerror(MMSE)estimateforthepathlossexponent,n; (b)calculatethestandarddeviationaboutthemeanvalue;(c)estimatethereceivedpoweratd = 2 kmusingtheresultingmodel;(d)predictthelik
17、elihoodthatthereceivedsignal level at 2 km will be greater than -60 dBm; and (e) predict thepercentageofareawithina2kmradiuscellthatreceivessignalsgreaterthan-60dBm,giventheresultin(d).Example38/2/202419The value of n which minimizes the mean square error can be obtained byequatingthederivativeofJ(n
18、) tozero,andthensolvingforn.(a)UsingEquation(3.11),wefind=pi(d0)-10nlog(di/100m).RecognizingthatP(d0) = 0 dBm,wefindthefollowingestimatesforp,indBm:TheMMSEestimatemaybefoundusingthefollowingmethod.Letpibethereceivedpoweratadistancedi,andletbetheestimateforpiusingthepathlossmodel of Equation (3.10).
19、The sum of squared errors between the measured andestimatedvaluesisgivenbySettingthisequaltozero,thevalueofn isobtainedasn = 4.4.8/2/202420(b)The sample variance 2 = J(n)/4 at n = 4.4 can beobtainedasfollows.therefore=6.17dB,whichisabiasedestimate.8/2/202421(c)The estimate of the received power at d
20、 = 2 km is(d)The probability that the received signal level will be greater than -60 dBm is(e)67.4% of the users on the boundary receive signals greater than-60 dBm, then 92% of the cell area receives coverage above 60dbm 8/2/2024223.5 Outdoor Propagation ModelsOkumura Model(150-1920MHz,1km-100km)Ha
21、ta Model(150-1500MHz,1km-20km)Egli Model(40-400MHz,0-64km)8/2/202423notprovideanyanalyticalexplanationitsslowresponsetorapidchangesinterrainOkumuraModel8/2/202424Okumuramedianattenuationandcorrection8/2/202425Find the median path loss using Okumuras model for d = 50 km, hte = 100 m, hre = 10 m in a
22、suburban environment. If the base station transmitter radiates an EIRP of 1 kW at a carrier frequency of 900 MHz, find the power at the receiver (assume a unity gain receiving antenna). Example 48/2/202426HATAmodel&COST231extension8/2/202427Example 5In the suburban of a large city, d = 10 km, hte =
23、200 m, hre = 2 m , carrier frequency of 900 MHz, using HATA s model find the path loss.8/2/2024283.6Indoorpropagationmodels8/2/202429FeatureofIndoorRadioChannelThedistancescoveredaremuchsmaller,andthevariabilityoftheenvironmentismuchgreaterforamuchsmallerrangeofT-Rseparationdistances.Ithasbeenobserv
24、edthatpropagationwithinbuildingsisstronglyinfluencedbyspecificfeaturessuchasthelayoutofthebuilding,theconstructionmaterials,andthebuildingtype.Indoorradiopropagationisdominatedbythesamemechanismsasoutdoor:reflection,diffraction,andscattering.However,conditionsaremuchmorevariable.8/2/202430Pathattenu
25、ationfactorsPartitionLossesinthesamefloorPartitionLossesbetweenFloors(floorattenuationfactors,FAF)8/2/202431Log-distancePathLossModelIndoorpathlosshasbeenshownbymanyresearcherstoobeythedistancepowerlawWherethevalueofndependsonthesurroundingsandbuildingtype,andXrepresentsanormalrandomvariableindBhavi
26、ngastandarddeviationofsigma.Thisisidenticalinformtothelog-normalshadowingmodelofoutdoorpathattenuationmodel.8/2/202432AttenuationFactorModelWhere nSF represents the exponent value for the “same floor” measurement. The path loss on a different floor can be predicted by adding an appropriate value of
27、FAF8/2/202433SignalPenetrationintobuildingsRF penetration has been found to be a function of frequency as well as height within the buildingMeasurements showed that penetration loss decreases with increasing frequency. Specifically, penetration attenuation values of 16.4dB, 11.6dB,and 7.6dB were mea
28、sured on the ground floor of a building at frequencies of 441MHz, 896.5MHz, and 1400Mhz, respectly.Results showed that building penetration loss decreased at a rate of 1.9dB per floor from the ground level up to the fifteenth floor and then began increasing above the fifteen floor.8/2/202434RayTraci
29、ngandSiteSpecificModeling In recent years, the computational and visualization capabilities of computers have accelerated rapidly. New methods for predicting radio signal coverage involve the use of Site Specific (SISP) propagation models and graphical information system (GIS) database. SISP models
30、support ray tracing as a means of deterministically modeling any indoor or outdoor propagation environment. Through the use of building databases, which may be drawn or digitized using standard graphical software packages, wireless system designers are able to include accurate representations of bui
31、lding and terrain features.8/2/202435Exercises1. If a transmitter produces 50W of power, express the transmit power in units of (a) dBm, and (b) dBW. If 50 W is applied to a unity gain antenna with a 900 MHz carrier frequency, find the received power in dBm at a free space distance of 100 m from the
32、 antenna. What is Pr(10 km)? Assume unity gain for the receiver antenna.2.If the base stations use 20 W transmitter powers and 10 dBi gain omnidirectional antennas, determine the cell coverage distance d. Let n = 4 and the standard deviation of 8 dB hold as the path loss model for each cell in the city. Also assume that a required signal level of -90 dBm must be provided for 90% of the coverage area in each cell. Assume d0 = 1 km .(Q(0.7)=0.24,f=900MHz)8/2/202436
