《柴诚进主编化工原理第二版下册答案》由会员分享，可在线阅读，更多相关《柴诚进主编化工原理第二版下册答案（140页珍藏版）》请在金锄头文库上搜索。
1、1. 82. 25 101.3 kPa3.0%350 g/m351066.1EkPa997.8 kg/m3CO2 33350/1000kmol/m0.008kmol/m44c3t997.8kmol/m55.4318ckmol/m3CO2 4t0.0081.4431055.43cxc 54*1.66101.44310kPa23.954pExkPaCO2t101.30.03kPa3.039ppykPa *pCO2CO2*(23.9543.039)kPa20.915pppkPa3. 110.5 kPa0.032y31.06koml/mckG=5.210-6 kmol/(m2skPa)kL=1.551
2、0-4 m/sH0.725 kmol/(m3kPa)1pc 2(1) t1.06*(110.50.032)kPa2.0740.725cppppyHkPa246GLG11111()(mskPa)/kmol0.7251.55105.210KHkk35252(8.899101.92310)(msPa)/kmol2.01210(msPa)/kmol 6G1097.4Kkmol/(m2skPa)33*(110.50.0320.7251.06)kmol/m1.504kmol/mcccpHcm/s10855.6m/s102.5725.01055.11111664GLLkHkK2 %58.95%100102.
3、51097.4/1/166GGGGkKKk4. 105.0 kPa25 2.126kmol/(m3kPa)7.5 kPa2.85 kmol/m3kL=2.1210-5 m/sKG1.20610-5 kmol/(m2skPa)1kGkxky2KLKXKY3 2 (1) 25 0.997kg/m3 3t997.0kmol/m55.3918ckmol/m35232xtL55.392.1210kmol/(ms)1.17410kmol/(ms)kck 255GGL11111()(mskPa)/ kmol1.206102.1262.1210kKHk 426.07310(mskPa)/ kmol52G1.
4、64710kmol(mskPa)k5232ytG105.01.64710kmol/(ms)1.72910kmol/(ms)kpk265GL10673.5m/s126.210206.1HKKm/s248.0180.105126.20.997SMHpm22233yyx1110.248()(ms)/kmol7.89610(ms)/kmol1.729101.17410mKkk32y1.26610kmol(ms)K 3242xy0.2481.26610kmol/(ms)3.14010kmol/(ms)KmK 6242XtL55.395.67310kmol/(ms)3.14210kmol/(ms)KcK5
5、232YtG105.01.20610kmol/(ms)1.26610kmol/(ms)KpK3 62AL*5.673102.1267.52.85kmol/(ms)NKcc 521.31010kmol/(ms)5. 101.3 kPa25 y1=0.04y2=0.0024.13103 kPa1.451 2 1013 kPa11110.040.0417110.04yYy2220.0020.002110.002yYy3t4.131040.77101.3Emp02Xn,L12n,V12min0.04170.00238.81/0.0417/40.770qYYqYmXn,Ln,Ln,Vn,Vmin1.451.4538.8156.27qqqq 3 n,V41122n,L10.04170.00207.0541056.27qXYYXq2 3t4.13104.0771013Empn,L12n,V12min0.04170.0023.8810.0417/04.077qYYqYmXn,Ln,Ln,Vn,Vmin1.
