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1、大连市 2012 年初中毕业升学考试试测（二）数学 参考答案及评分标准1 D2 A3 C4A5B6B7C8D9 210 a 611. x21213 1201417815 816817=3( 222 1)4 2 8= 6 2 . 918原式y(xy)( xy)( xy)4x yy( xy)17x y= y.919ABCDAB =DC , BAD = CDAB= C. 3 EAD= EDABAD EAD = CDA EDABAE= CDE5ABEDCE7BE =CE .9ADBEC201 100 14 0.61 .62 0.25 360 =90 8 “ ” 90 .93 1200 61 100%
2、= 73211100 “ ” 7321250225x .321.1 y xxx22160 cm2- x 2 25 x =160x 2 25 x 160=05=b2 4ac=( 25)2 41160 = 15 078160cm2.9221 180 60.22v乙/（ 1） 80v5180 160乙3v 乙 = 9061 180902833A29323 1CDO1ODBOD=2 DEB =2 45 =902ABCDAB/DC3CDO=180BOD =180 90 =90OD CDCDO42AEBDABE= ADEABCDAB=DC= 6ABOAEB=906DCRt ABEcos ABE= BE =
3、 cos ADE =2AB3BE =263AOBFEBE=2 27BF DE BFE=90BF= BE sin45 = 2 22282BOD=90 OB=DO= 3BDOB2OD 232323 29DFBD 2BF 2(32) 22214 .1024.1BD= 2t CE=t.ADE1FDEFDE=DFEDF =60.CEDB 图 1DFB = EDF B=6030=30= BDF =DB= 2t . 2BC=CE+ED +DBt+2t+2t=15t=3.3DE2ADE =EF=EB= CBCE= 15t BD = 2tFDB=2 BE2t = 2(15 t) t = 15 .2C (D)EB
4、t=3s 15sFAB .5图 22(2) 0 t 3 (3)(1)DE=EF=FD =15 3t=3(5 t) DH =DB= 2tFH =15 3t 2t= 15 5t=5(3 t).6DEF = EFD = 60 B=30 AFEGB=180 GEB B=180 6030=90.GRt FGHH535(3t) .CEMDBGH=FHsin60 =(3t)FG=FHcos60 =22图 3S FGH1 FGGH253 (3 t ) 2 .728FM DEM.FM =EFsin60 =33(5t ) .2S FED1 EDFM93 (5t )2824SS FEDSFGH=73 t 2 15
5、3 t2253 .9848DBC15 s . t+2t=15t=5D2E.13 t 15t 5DE2DEFABC(4).S SFED1 DEFM=93 (5 t )293 t 245 3 t2253.2442473t 2153t2253(0t3)11S8489 3 t 2453 t2253(3t15 ，且 t5).4242AFCEMDB图 425DFACDF1 AC22MMGADDFGEMG = NBMG= BAD3MEG= NED ME =NEMEGNEDMG =DN4BM =DNMG =BM5GHBCHAG CG6ADNABCDAB=BC=CD=DABAD = B= ADC=907EGMB
6、 = B= GHB =90MFMBHG8GMG =MBMBHG9BHMG = GH= BH= MB , AMG = CHG =90AM=CH AMG CHGGA=GCDA=DCDGAC ADC =90 DA=DCC1011DF1 AC2DFACDF1 AC122261B10C31D01.1ACy = kx bkb3,k1,3kb 1.2b5y.2y1 x5 .222OEF5005EBx3D2Cy=a(x 1)(x 5)FAM5a( 1)5,a =12.2y1x22x5 .4222BDM.BDy=k1x+b1k1b1 0,k11,b11.b11.y=x 1.5Mm m 1m11 m22m5 ,622m1= 3 m2=1 ().M34 .73D AC PDPAC G BP.BP .1OE=5OF = 5OD =1y2DF= 3EF= 52(5)255.8222DGF =EOF =90DFG =EFOHEOBxDDGFEOFCDG DF GF9GFEO EFOFPDG= EO DF35 GF= OFDF35 .EF5EF10DP=2 DG= 65 .5PQ yPH xQ、H.
