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1、新课程课堂同步练习册(九年级数学下册人教版)答案数学课堂同步练习册(人教版九年级下册)参考答案 第二十六章 二次函数 26.1 二次函数及其图象(一) 2一、 D C C 二、 1. ?0,=0,?0,=0,?0 =0, 2. y,x,6x3. ,二 y,x(10,x)122三、1. y,x 2.(1)1,0,1 (2)3,7,-12 (3)-2,2,0 3. y,3x16?26.1 二次函数及其图象(二) 2一、 D B A 二、1. 下,(0,0),轴,高 2. 略 3. 答案不唯一,如 yy,2x三、1.的符号是正号,对称轴是轴,顶点为(0,0) 2. 略 ya23. (1) (2) 否
2、 (3) 3,6,;,3,6 y,2x,?26.1 二次函数及其图象(三) 一、 BDD 二、1.下, 3 2. 略 三、1. 共同点:都是开口向下,对称轴为y轴( 12a,不同点:顶点分别为(0,0);(0,,);(0,,) .2. 3. y,3x,54?26.1 二次函数及其图象(四) x,3一、 , 二、1. 左,,, 2. 略 3. 向下,(,,,) 112a,三、1. 2. 3. yx,3 ac,3,2,34?26.1 二次函数及其图象(五) x,1一、C D , 二、1. ,(1,1) 2. 左,1,下,2 3.略 22yx,,,12三、1.略2(1) (2)略 3. (1) ,a
3、,6h,2k,3y,6(x,2),3(2)直线 x,2223小2yx,,,122(1) (2)略 ,?26.1 二次函数及其图象(六) 3731(,)直线x,;,5一、B B D D 二、1. 2. 5; 3. 2224212b4acb,222y(x4)6y3(x)ya(x),,三、1. 略 332a4a22. 解:(1)设这个抛物线的解析式为(由已知,抛物线过A(20),,B(10),yaxbxc,,steel bolts, screws and studs GB/T3098.6-2000 scope of this project are: 1, 2, 3 aluminium sheet
4、curtain wall of glass curtain wall and the Aluminum plastic Board curtain wall 4, and stone curtain wall 5, and curtain wall buried pieces 6, and light steel points type glass rain canopy, and aluminum Board rain canopy 7, and aluminum Venetian 8, and outdoor advertising (containing roofing and the
5、State surface advertising) 9 to spring glass door 10, and concrete structure and curtain wall between of layer between, and around fire seal blocking 11, and anti-mine 12, and daughter wall top processing 13, and pan light ming, engineering of tie construction 14, and buildings of deformation sewing
6、 (settlement sewing, and expansion joints,) 15, and After the detailed design drawings issued a wall embedded part is inconsistent with the tenderer needs to increase fixed curtain wall structure 16, decorative surfaces and decorative surface and joints between parts of other buildings facing sealin
7、g process, required to support the outer decoration of a hole, hole, plugging holes and so on. This works more decorative items, in order to ensure that the decoration construction progress and quality, trying to avoid construction does not . Processing. After installation is complete if you have da
8、maged galvanized parts should 420abc,,,,a,2,abc,,0,b,2三点,得解这个方程组,得 ( C(28),,428abc,,(c,4,2所求抛物线的解析式为( yxx,,,224?219,22(2)( yxxxxx,,,,,,,2242(2)2,22,19,该抛物线的顶点坐标为( ?,,,22,?26.2 用函数观点看一元二次方程 33,1,x,一、 C D D 二、1.(-1,0);(2,0) (0,-2) 2. 一 3. ; ; 或,1223xx,1或x,1x,3 三、1.(1)或 (2),-1或,3 xx212,126,0,26,0,(3),3
9、 2.(1)yx,,23 (2)和 x,2?26.3 实际问题与二次函数(一) 2,2一、 A C D 二、1. 大 18 2. 7 3. 400cm 2三、1.(1)当矩形的长与宽分别为40m和10m时,矩形场地的面积是400m 2(2)不能围成面积是800m的矩形场地. 2(3)当矩形的长为25m、宽为25m时,矩形场地的面积最大,是625m 2. 根据题意可得:等腰直角三角形的直角边长为,矩形的一边长为. 2xm2xm20422,,x,,,1022x其相邻边长为 ,21,Sxxxx,,,2102222?该金属框围成的面积 ,220,,32220xx1052, (,x,) ,10当时,金属
10、框围成的面积最大. x,30202322,260402xm,此时矩形的一边长为, ,10221032210210,,,m相邻边长为. ,aged galvanized parts shouldon progress and quality, trying to avoid construction does not . Processing. After installation is complete if you have damtructition of a hole, hole, plugging holes and so on. This works more decorative
11、items, in order to ensure that the decoration consd decorative surface and joints between parts of other buildings facing sealing process, required to support the outer decoraces aned a wall embedded part is inconsistent with the tenderer needs to increase fixed curtain wall structure 16, decorative
12、 surfand buildings of deformation sewing (settlement sewing, and expansion joints,) 15, and After the detailed design drawings issumine 12, and daughter wall top processing 13, and pan light ming, engineering of tie construction 14, a-seal blocking 11, and anti ace advertising) 9 to spring glass doo
13、r 10, and concrete structure and curtain wall between of layer between, and around firee surfn canopy, and aluminum Board rain canopy 7, and aluminum Venetian 8, and outdoor advertising (containing roofing and the Statastic Board curtain wall 4, and stone curtain wall 5, and curtain wall buried piec
14、es 6, and light steel points type glass rai2000 scope of this project are: 1, 2, 3 aluminium sheet curtain wall of glass curtain wall and the Aluminum pl-steel bolts, screws and studs GB/T3098.62 2 Sm,1003223002002.,最大26.3 实际问题与二次函数(二) 25212.5一、A B A 二、1. , 2. 3.或 50(1),x2 x,7.5三、1. 40元 当元时,元 W,625最
15、大22. 解:(1)降低x元后,所销售的件数是(500+100x),y=,100x+600x+5500 (0,x?11 ) 22(2)y=,100x+600x+5500 (0,x?11 )配方得y=,100(x,3)+6400 当x=3时,y的最大值是6400元。即降价为3元时,利润最大。所以销售单价为10.5元时,最大利润为6400元。答:销售单价为10.5元时,最大利润为6400元. m,x,1003.(1)(0?x?100) (2)每件商品的利润为x,50,所以每天的利润为: y,(x,50)(,x,100)2?函数解析式为 yxx,,,1505000150(3)? 在50,x,75元时,每天的销售利润随着x的增大而增大 x,752,(,1)26.3 实际问题与二次函数(三) 2一、 A C B 二、 1. 10( 2. 3. 3 yRR,,30,三、1.(1)矩形广场四角的小正方形的边长为35米或者10米( (2)当矩形广场四角的小正方形的边长为22(5米时,所铺设设铺设矩形广场地面的总费最小,最少费用为199500元( 12y,(x,6),5215,6)2. (1 (2)( 1232AD,30,x(cm)3. (1) (2)当( x,20cm时,y取最大值为300cm4第二十七章 相似 ?27