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1、12011.深圳中考 深圳某科技公司在甲地、乙地分别生产了 17 台，15 台同一种型号的检测设备，全部运往大运赛场 A、B 两馆，其中运往 A 馆 18 台、运往 B 馆 14 台； 运往 A、B 两馆的运费如表 1：出发地目的地 甲地乙地A 馆800 元/台700 元/台B 馆500 元/台600 元/台（1）设甲地运往 A 馆的设备有 x 台，请填写表 2，并求出总运费 y（元）与 x（台）的函数关系式；（2）要使总运费不高于 20200 元，请你帮助该公司设计调配方案，并写出有哪几种方案；（3）当 x 为多少时，总运费最小，最小值是多少?出发地目的地 甲地乙地A 馆x18xB 馆（）1
2、7x15(18)x分配原则：产地的 17 台、15 台必须运走，场馆必须得到 18 台、14 台甲地A 馆 x 台，则甲地还剩（）台，这（）台就运给 B 馆了 17x17x此时 A 馆得到了 x 台，共需要 18 台，还需要（）台，18x这（）台只能从乙地运过来，18x 乙地总共的 15 台里运了（）台给 A 馆， 剩余的只能给 B 馆，为即（x-3）18x15(18)x解：（1）总费用800500(17)700(18)600(3)yxxxx整理得：20019300yx余 余 15-(18-x)余 余 BA余 余 x余 余 余 余 (18-x)余乙 乙 (17-x)乙 乙 Bx乙 乙 乙 15
3、乙B 乙 乙 14乙A 乙 乙 18乙乙 乙 乙 17乙2（2）此调配过程中需满足，解得0 170 180 30x x x x 317x总运费不高于 20200 元，y2001930020200x解得4.5x 的取值范围为 又为正整数x34.5xx =3、4 故共有两种方案，下面过程省略x类型题：上周周末作业八年级下数学期末复习.加深内部资料，请勿外传！#XuyUP2kNXpRWXmA&UE9aQGn8xp$R#͑GxGjqv$UE9wEwZ#QcUE%&qYpEh5pDx2zVkum&gTXRm6X4NGpP$vSTT#&ksv*3tnGK8!z89AmYWpazadNu#KN&Mu
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