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1、Shandongsteeltrawlerof 104gross tonnagePropellerdesign document Instructor： Studentname: StudentID: u200816943 Class: 0803 Completion Date:2011/5/261. Main parameters ofthe hullShip Type: Single Propeller Engines Afterward SteelTrawlerLWL27.5mCb0.502LPP26.0mCp0.592Breadth5.40mB/Tm2.84Depth2.50m137.3
2、5tAverage Draft1.90mXb-0.78mAft Draft2.40mZs0.35mEstimate the hulleffective power by the method of AyreSpeed v（kn）91011Speedlength ratio V/L1/20.971.081.19Froude numbers Vs/(gL)1/20.290 0.322 0.354 Standard C0 look up the diagram 7-3295243205Standard Cbc look up the table 7-50.5930.560.546Real Cb（fa
3、tter or thinner）（%）15.35，thinner10.36，thinner8.06，thinnerCbs amendment（%）11.217.1745.104Cbs amended amount 1331710Amended Cb 1328260215B/T amendment（%）=-10Cb（B/T-2）%-4.2168-4.2168-4.2168amount of B/T amendment，2-14-11-9C2 after Amended B/T C2314249206Standard Xc，%L，before or after amidships1.838 Aft
4、er amidships2.327After amidships2.495After amidshipsReal Xc，%L，before or after amidships3，after amidships3，after amidships3，after amidshipsDifference %L，before or after the standard Xc 1.162，after0.6725，after0.5045，afterXcs amendment（%）look up the table 7-7（b）0.220.50.96amount of Xcs amendment，3 Equ
5、ation (7-24)-1-1-2the C3 after amend Xc 313248204Amendment of the length （%）=（Lwl-1.025Lbp）/Lwl*100%3.23.23.2Amuont of the amendment of length 4 Equation (7-25)1087the C4 after amend length323256211Vs372910001331Pe=0.64*Vs3/C4*0.735(KW)39681092. the Parameters of the engineMainenginetype6160A-123Pow
6、er（KW）136Rotational speed（rpm）850 Gearbox type2HC250Reduction ratio1.97:13. Estimation of the promoting factors (1) Wake Fraction This ship is a single screw steel trawler,so we can use Hankexieer formula to estimate the wake fraction :=0.77Cp-0.28So the wake fraction is 0.176.(2) Thrust Deduction F
7、raction To the single screw steel trawler ,the thrust deduction fraction t can also be estimated by the Hankexieer formula:t=0.77 Cp-0.30 So the thrust deduction fraction t is 0.156 (3) Relative Rotative Efficiency Because of the lack of data, we approximately value the relative rotative efficiency
8、R 1.0. (4) Hull Efficiency H =(1-t)/(1-)=(1-0.156)/(1-0.176)=1.024.Number of Blades According to the general conditions, the number of the blades of the single paddle ship is usually 4. Whats more ,we have more detailed charts of 4-blade propeller, so, we chose the 4-blade propeller.5 Estimation of
9、the AE/A0 Estimate the AE/A0 by the formula: AE/A0 = (1.3+0.3Z)T / (P0-Pv)D 2 + kAmong this ,in the design speed, PE=71.5KW,V=10.1kn,T=PE/(1-t)V=71.5/(1-0.156）10.10.5144)=16.31kN,When the temperature of the water is 15,the Pv=1.705 kN/m2.The static pressure is P0=Pa+hs=(10330+1025(2.4-0.35)9.8N/m2=1
10、21.83kN/m2Value the k 0.2Get the D is 1.5m from the hull lines.So the AE/A0 = (1.3+0.3Z) T / (P0-Pv)D 2 + k=（1.3+0.34）16.31/(121.83-1.705) 1.52)+0.2=0.3516. Introduction to the choice of the impeller At present ,in the designing of the cargo ship, the designers mainly use the B-screw series and the
11、MAU-screw series. Now ,we choose the MAU-screw series.7. Choose two or three charts ,then calculate the maximum speed. Choose the MAU4-40,MAU4-55,MAU4-70 charts.Suppose the reserve power is ten percent of the rated power, the shaft transmission efficiency S=0.98 and the gear efficiency G=0.96.The po
12、wer the propeller received is PD0，PD0=Ps0.9SGR=115.14KW=156.67hp8. Go on with the final design with the charts chose in the previous step ,and obtain three groups of parameters of the propeller and the maximum speed.in which, the rotation speed of the propeller is N=n/i=850/1.97=431.47r/minWith the-
13、 charts of the MAU4-40,MAU4-55,MAU4-70,we obtain the data in the following table:Item unitnumberAssumed speed Vkn9.000 10.000 11.000 VA=（1-）*Vkn7.416 8.240 9.064 Bp=N*PD0.5/VA2.536.059 27.709 21.835 Bp1/2 6.005 5.264 4.673 MAU4-4070.000 63.000 57.000 P/D0.680 0.710 0.750 O0.580 0.615 0.643 PTE=PDOHO
14、hp93.077 98.693 103.187 MAU4-5568.500 61.000 55.000 P/D0.720 0.760 0.810 O0.565 0.595 0.630 PTE=PDOHOhp90.670 95.484 101.101 MAU4-7067.000 60.400 54.500 P/D0.730 0.770 0.830 O0.545 0.575 0.595 PTE=PDOHOhp87.460 92.274 95.484 With the data in the table, we can draw the following diagram that the PTE, and
