《基于51单片机的频率计设计-c语言程序》由会员分享，可在线阅读，更多相关《基于51单片机的频率计设计-c语言程序（19页珍藏版）》请在金锄头文库上搜索。
1、基于51单片机的频率计设计，c语言程序代码1：#include#define uint unsigned int#define uchar unsigned char#define ulong unsigned longsbit dula=P26;sbit wela=P27;sbit key1=P10;sbit key2=P11;sbit key3=P12;uchar tt=0,mode;ulong num,num1;uchar code shu=0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79
2、,0x71;void delay(uint z)uint i,j;for(i=z;i0;i-) for(j=110;j0;j-);void display(uchar a,uchar b,uchar c,uchar d,uchar e,uchar f)dula=1;P0=shua;dula=0;P0=0xff;wela=1;P0=0xfe;wela=0;delay(3);dula=1;P0=shub;dula=0;P0=0xff;wela=1;P0=0xfd;wela=0;delay(3); dula=1; P0=shuc; dula=0;P0=0xff;wela=1;P0=0xfb;wela
3、=0; delay(3);dula=1; P0=shud; dula=0;P0=0xff;wela=1;P0=0xf7;wela=0; delay(3);dula=1; P0=shue; dula=0;P0=0xff;wela=1;P0=0xef;wela=0; delay(3); dula=1; P0=shuf; dula=0;P0=0xff;wela=1;P0=0xdf;wela=0; delay(3);ulong read() uchar t1,th1,th2; uint val; while(1) th1=TH1;t1=TL1;th2=TH1;if(th1=th2)break; val
4、=th1*256+t1;return val;void keyscan() if(key1=0)mode=1;TMOD=0X90;TH1=0; TL1=0;ET1=1;TR1=1;EX1=1;EA=1;IT1=1;ET0=0;if(key2=0)mode=2; TMOD=0X51; TH0=(65536-50000)/256; TL0=(65536-50000)%256; TH1=0; TL1=0; ET0=1;ET1=1; TR1=1; TR0=1;EX1=0; EA=1;if(key3=0)mode=3;TMOD=0X51;TH0=(65536-50000)/256; TL0=(65536
5、-50000)%256;TH1=0;TL1=0;ET0=1;ET1=1;TR1=1;TR0=1;EX1=0;EA=1;void main()uint aa,bb,cc,dd,ee,ff;while(1)keyscan(); if(mode = 1) aa=num/100000;bb=num/10000%10;cc=num/1000%10;dd=num/100%10;ee=num/10%10;ff=num%10;display(aa,bb,cc,dd,ee,ff);if(mode =2) num=num1*2; aa=num/100000;bb=num/10000%10;cc=num/1000%
6、10;dd=num/100%10;ee=num/10%10;ff=num%10;display(aa,bb,cc,dd,ee,ff);if(mode=3)num=500000/num1; aa=num/100000;bb=num/10000%10;cc=num/1000%10;dd=num/100%10;ee=num/10%10;ff=num%10;display(aa,bb,cc,dd,ee,ff);void T0_time() interrupt 1TH0=(65536-50000)/256; TL0=(65536-50000)%256;tt+;if(tt=10)tt=0; num1=re
7、ad();TH1=0;TL1=0;void exter() interrupt 2num=read()+1;TH1=0;TL1=0;代码2：#include#define uint unsigned int#define uchar unsigned char#define ulong unsigned longsbit dula=P26;sbit wela=P27;sbit key1=P10;sbit key2=P11;sbit key3=P12;uchar tt=0,mode;ulong num,num1;uchar code shu=0x3f,0x06,0x5b,0x4f,0x66,0x
8、6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71;void delay(uint z)uint i,j;for(i=z;i0;i-) for(j=110;j0;j-);void display(uchar a,uchar b,uchar c,uchar d,uchar e,uchar f)dula=1;P0=shua;dula=0;P0=0xff;wela=1;P0=0xfe;wela=0;delay(3);dula=1;P0=shub;dula=0;P0=0xff;wela=1;P0=0xfd;wela=0;delay(3); dula
9、=1; P0=shuc; dula=0;P0=0xff;wela=1;P0=0xfb;wela=0; delay(3);dula=1; P0=shud; dula=0;P0=0xff;wela=1;P0=0xf7;wela=0; delay(3);dula=1; P0=shue; dula=0;P0=0xff;wela=1;P0=0xef;wela=0; delay(3); dula=1; P0=shuf; dula=0;P0=0xff;wela=1;P0=0xdf;wela=0; delay(3);ulong read() uchar t1,th1,th2; uint val; while(
10、1) th1=TH1;t1=TL1;th2=TH1;if(th1=th2)break; val=th1*256+t1;return val;void keyscan() if(key1=0)mode=1;TMOD=0X90;TH1=0; TL1=0;ET1=1;TR1=1;EX1=1;EA=1;IT1=1;ET0=0;if(key2=0)mode=2; TMOD=0X51; TH0=(65536-50000)/256; TL0=(65536-50000)%256; TH1=0; TL1=0; ET0=1;ET1=1; TR1=1; TR0=1;EX1=0; EA=1;if(key3=0)mod
11、e=3;TMOD=0X51;TH0=(65536-50000)/256; TL0=(65536-50000)%256;TH1=0;TL1=0;ET0=1;ET1=1;TR1=1;TR0=1;EX1=0;EA=1;void main()uint aa,bb,cc,dd,ee,ff;while(1)keyscan();P1=0xff; if(mode = 1) key1=0; aa=num/100000;bb=num/10000%10;cc=num/1000%10;dd=num/100%10;ee=num/10%10;ff=num%10;display(aa,bb,cc,dd,ee,ff);if(mode =2) key2=0;num=num1*2+3; aa=num/100000;bb=num/10000%10;cc=num/1000%10;dd=num/100%10;ee=num/10%10;ff=num%10;display(aa,bb,cc,dd,ee,ff);if(mode=3)key3=0;num=500000/num1; aa=num/100000;
