《设备机械基础解答.ppt》由会员分享，可在线阅读，更多相关《设备机械基础解答.ppt（55页珍藏版）》请在金锄头文库上搜索。
1、第第1 1章章 习题解答习题解答8/14/20248/14/2024.1.1-1TANCG1 1TBNCG2 2TAG1 1TBG2 2Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.2.1-3ABPBNBNAyNAxEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Pro
2、file 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.3.补充：补充：FABCDRDABCRBNAyNAxNCyNCxNCyNCxFDCEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.4.整体受力图：整体受力图：FABCDABCRBNAy
3、NAxNCyNCxRDNCyNCxFDCNAyNAxRBRDEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.5.1-71、判断、判断BC为二力杆，取为二力杆，取AB为研究对象，画其受力图：为研究对象，画其受力图：2、建立坐标，列平衡方程：、建立坐标，列平衡方程：GABCG45NBCNAyNAxGABCG45400720Evaluation only
4、.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.6.GABCG45NBCNAyNAxEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024
5、.7.补充：补充：NAyNAxNBABFqMCDEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.8.1-9（a）PPACBD321Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty
6、Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.9.PPACBDPEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.10.1-9(b)2P2PACBDPP321Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Co
7、pyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.11.2P2PACBDPPPPPEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.12.补充：知补充：知A A100mm100mm2 2、E E2 210105 5MPaMPa，F F10KN10KN、Q Q4KN4
8、KN，画轴力图，求应力、变形画轴力图，求应力、变形QQACBDFFEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.16.轴力图：轴力图：QQACBDFF6KN10KN10KN总变形：总变形：Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.C
9、opyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.17.1-11分析：分析：支架要安全，支架要安全，则要保证则要保证ABAB、BCBC杆均安全。杆均安全。Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.18.判断：判断：ABAB、BCBC均为二均为二力杆，取力杆
10、，取B B铰为研究铰为研究对象，其受力图为：对象，其受力图为：B B由平衡方程可得：由平衡方程可得：Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.19.强度校核：强度校核：所以，支架安全。所以，支架安全。Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5
11、.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.20.1-12(a)10KN.m10KN.m15KN.m15KN.m20KN.m20KN.m30KN.m30KN.m30KN.m30KN.m10KN.m10KN.m5KN.m5KN.m15KN.m15KN.mEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1
12、章章 习题解答习题解答8/14/20248/14/2024.21.1-12(b)2 2M4 4MMMM2 2M2MEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.22.1-13MTEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyri
13、ght 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.23.1-13MTEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.24.1-14Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile
14、5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.25.Q、M正负号的规定：正负号的规定：1 1、对于剪力、对于剪力Fs s以该截面（如以该截面（如n-nn-n）为界，如左段相对右）为界，如左段相对右段向段向上上滑移（简称滑移（简称左上右下左上右下），则剪力为），则剪力为正正；反之为负。；反之为负。2 2、对于弯矩、对于弯矩M若梁在该截面附近弯成若梁在该截面附近弯成上凹下凸上凹下凸，则弯矩，则弯矩为为正正；反之为负。；反之为负。Evaluation only.Created with As
15、pose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.26.1-15(a)xEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.27.1-15(b)(1)(1)求支座反力：
16、求支座反力：RARCPACBEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.28.10ACBRARCACAC段：段：x1CBCB段：段：PACBRARCx2（2 2）分段列）分段列Q Q（x x）、）、MM（x x）。）。Evaluation only.Created with Aspose.Slides for .NET 3.5 Client P
17、rofile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.29.PACBRARCEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.30.1-15(c)AC段：段：CB段：段：Evaluation only.Created with Aspo
18、se.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.31.Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.32.1-15(d)AC段：段：Evaluation only.
19、Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.33.1-15(d)CB段：段：Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.34
20、.Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.35.1-15(e)AC段：段：CB段：段：Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题
21、解答8/14/20248/14/2024.36.Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.37.1-15(f)(1)(1)求支座反力：求支座反力：RARBRAEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004
22、-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.38.RARBRAACAC段：段：x1CDCD段：段：x2（2 2）分段列）分段列F Fs s（x x）、）、MM（x x）。）。RARBRAEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.39.RARBRADBDB段：段：x3Evalu
23、ation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.40.1-15(g)Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/20
24、24.41.1-15(h)(1)(1)求支座反力：求支座反力：RARBqACBEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.42.(2)(2)分段列剪力、分段列剪力、弯矩方程：弯矩方程：RARBqACBx1ABAB段：段：Evaluation only.Created with Aspose.Slides for .NET 3.5 Client
25、Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.43.(2)(2)分段列剪力、分段列剪力、弯矩方程：弯矩方程：RARBqACBx2BCBC段：段：Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.44.(3)(3)画剪力、弯矩图
26、：画剪力、弯矩图：RARBqACBEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.45.1-16Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习
27、题解答8/14/20248/14/2024.46.1-20解：解： 计算柔度一端固定，一端自由一端固定，一端自由 =2=2，Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.47.可见，螺杆的稳定性不够。可见，螺杆的稳定性不够。 计算临界力 稳定性校核稳定性校核Evaluation only.Created with Aspose.Slides fo
28、r .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.48.判断：判断：ABAB、BCBC均为二力杆，均为二力杆，取取B B铰为研究对象，其受铰为研究对象，其受力图为：力图为：由平衡方程可得：由平衡方程可得：B B1-221-22Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pt
29、y Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.49.强度校核：强度校核：所以，综合二杆，许可载荷为所以，综合二杆，许可载荷为Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.50.1-231-23属双剪结构。属双剪结构。取销钉为研究对象，取销钉为研究对象，其受力情况如图其受力情况如图b b所示。所示。销钉中间段部分
30、有二销钉中间段部分有二个受剪面个受剪面( (图图c)c)，每一，每一受剪面上的剪力、剪受剪面上的剪力、剪切面积为：切面积为：Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.51.因因2t2t2 2t t1 1，故取，故取厚度为厚度为t t1 1段的销钉为段的销钉为研究对象，挤压面上研究对象，挤压面上的的Evaluation only.Created
31、 with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.52.所以综合计算，取所以综合计算，取d d14mm14mm。Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14
32、/2024.53.1-241-24解解:(1):(1)剪切强度校核剪切强度校核 根据平衡条件可得键在剪切面上的根据平衡条件可得键在剪切面上的剪力剪力Fsbhd dFsEvaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.54.bhd d由剪切强度条件可得：由剪切强度条件可得：满足键的剪切强度条件。满足键的剪切强度条件。FsEvaluation only.
33、Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.第第1 1章章 习题解答习题解答8/14/20248/14/2024.55.（2 2）挤压强度校核）挤压强度校核 研究半个键上的平衡，知挤压力实际为剪力，故有：研究半个键上的平衡，知挤压力实际为剪力，故有： Fbs= =Fs=57.1KN=57.1KN 由挤压强度条件可得：由挤压强度条件可得：满足挤压强度条件。满足挤压强度条件。Evaluation only.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Copyright 2004-2011 Aspose Pty Ltd.
