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1、Java练习题、运行程序写结果1. 当在命令提示符后输入 ”ava SumT est 4 5 ”之后，下列程序的输出结果为:public class SumTestpublic static void main( Stri ng args)int a, b, sum;a=ln teger.parse In t(argsO);b=ln teger.parse In t(args1);sum=a+b;System.out.pri ntln(a + + + b + = + sum);2. 当在命令提示符后输入”ava PrintStar 8 ”之后，下列程序的输出结果为:public class P
2、rin tStar public static void main(String args) int n = In teger.parse In t(args0); int i;for( i=1; i=n; i+) System.out.pri nt(*);System.out.pri ntl n();3. 当在命令提示符后输入 java CalculateTest 5.5 之后，下列程序的输出结果为:public class CalculateTestpublic static void main(String args) float x,y;x = Float.parseFloat(arg
3、s0); if(x1)y = x;else if(1=x&x10)y = 2*x-1;elsey = 3*x-11;System.out.pri ntl n( y);4. 当在命令提示符后输入” java Factorial 3”之后，下列程序的输出结果为:public class Factorial3 public static void main( Stri ng args) int num = In teger.parse In t(args0);int result = 1;if(nu m1)System.out.pri ntl n(” 应输入大于 1 的整数！); elseint i
4、;for( i=1; i=num; i+)result = result*i;System.out.pri ntln (结果是：+result);5. 下歹y程序的输出结果为： public class Xpublic static void main( Stri ng args)String names=new String5;for(i nt x=0;xargsen gth;x+)n amesx=argsx;System.out.pri ntln(n ames2);6. 下歹u程序的输出结果为：public class Testpublic static void main(String
5、args) System.out.pri nt ( 3.5+1/2+56%10+);System.out.pri nt ( 3.5+1.0/2+56%10+);int a = 4%3*7+1;System.out.pri ntln( a );7. 下歹y程序的输出结果为：public class A1 public static void main(String args) int a= new int 5;a0=1;a1=2;a2=3;a3=4;a4=5;System.out.print(a+0+ = +a0+);System.out.pri nt(a+1+ = +a1+);System.o
6、ut.pri ntl n( a+2+ = +a2+);System.out.pri nt(a+3+ = +a3+);System.out.pri nt(a+4+ = +a4);8. 下歹y程序的输出结果为： public class array1D_1 public static void main(String args) int i;int a;a = new in t5;for(i=0;i=O;i_)System.out.print(“ a “ +i +”= t + i +”，9. 运行结果是：public class Test1 Stri ng str = new Stri ng(Hi
7、 !);char ch = L, i, k, e ;public static void main(String args) Test1 ex = new Test1();System. out .print(ex.str + );System. out .print(ex.ch);10. 运行结果是：public class Test3 public static void main( Stri ng args) int i;for (i = 3; i = 20; i +) if (i % 2) = 0)System. out .print(i + );11. 运行结果是：public cl
8、ass Test4 public static void main(String args) int i,sum=0;for (i = 3; i = 20; i +)if (i % 2) = 0) sum=sum+i;System. out.print(i=+i+,sum=+sum);12. 运行结果是：public class Test5 public static void main(String args) int i,sum=0;for (i = 1; i = 100; i +) if (i % 2) = 1) sum=sum+i;System.out.pri ntln( sum);1
9、3. 运行结果是class Test6 public static void main( Stri ng args) int i;for(i=0;i10;i+)System.out.pri nt(i+);if (i%2!=0) continue;System.out.pri ntln(” );14、运行结果是: public class Test14 public static void main(String args) int n = 1, m, j, i;for (i = 3; i = 30; i += 2) m = (int) Math.sqrt(double) i);for (j =
10、 2; j = m + 1) System.out.pri nt(i + );if (n % 5 = 0)System.out.pri nt(n);n+;15. 下歹y程序的输出结果为： public class Testi public static void main(String args) int y, x=1, total=0;while(x=10) y=x*x;System.out.pri nt(y+);total+=y;+x;System.out.pri nt(total is +total);16. 下歹y程序的输出结果为： public class WhileExamplep
11、ublic static void main(String args)String copyFromMe=Copy every letter un til you encoun ter u.;Stri ngBufer copyToMe=new Stri ngBuffer();/ 创建一个空的串变量int i=0;char c=copyFromMe.charAt(i);while(c!=u) copyToMe.appe nd(c);c=copyFromMe.charAt(+i); System.out.pri ntl n( copyToMe);17. 下歹y程序的输出结果为： public cl
12、ass BreakExamplepublic static void main(String args)in t array=32,87,3,589,12,1076,2000,8,622;int search = 1076, i=0, j=0;boolea n foun dIt = false;for (i=0; i3; i+) for (j=0; j3; j+)if (arrayij = search) foun dIt = true; break; / 跳出内层循环if(foundlt) break; / 跳出外层循环if(fou ndlt)System.out.println(Found
13、 + search + at i = + i +, j = + j); elseSystem.out.println(search + is not in the array);18. 下歹y程序的输出结果为： public class SumDemo2 public static void main( Stri ng args) int sum = 0, i = 0;doif(i%2=0)sum = sum+i;i+;while(i=20);System.out.pri ntl n(其最终和是：+sum);19. 下歹u程序的输出结果为：public class AddTest public static void main(String args) int nu m1, nu m2;num1 = 10;num2 = 20;System.out.pri ntln(n um1 + + + num2 + = + add( num1, num2); static int add(i nt op1,i nt op2)retur n op1+op2;20. 下歹y程序的输出结果为： clas
