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1、豆子編製 12/1/2004心理測驗SPSS上機:信度分析資料輸入Data輸入頁變項定義頁Reliability Analysis本次課題包含:如何進行各種信度分析1. 再測信度(Test-Retest Reliability)2. 複本信度(Alternate-form Reliability)3. 折半信度(Split-half Reliability)4. 內部一致性(Internal Consistency Coefficient)【計算係數】5. KR 20【壹】 再測信度(Test-Retest Reliability)某空間性向測驗有20題單選題,分別在十月與第二年四月施測同一組
2、10名學生,以下是測驗結果,請計算信度。PersonABCDEFGHIJOct18165131516125810Apr18186161716145711 步驟一 按【Analyze】【Correlate】【Bivariate】步驟二 會出現下面的對話框,將左邊兩變項選入右邊Variables內,在Correlation Coefficients方盒內選取Pearson;在Test of Significance方盒內選取Two-tailed;勾選最下面的Flag significant correlations,之後按鍵。補充 若想呈現平均及標準差則可在按鍵前按進入下個對話框,在Statist
3、ics的方盒內選取Means and standard deviations,按繼續。Correlations紙筆計算結果:PersonABCDEFGHIJOct1816513151612581011.84.4226Apr1818616171614571112.84.8744X1 X2324288302082552561682556110X1X2 =1720N=10【貳】 複本信度(Alternate-form Reliability)某自我概念量表,有20題是非題,題本A與B 分別施測同一組10個人,分數愈高表示愈具有正向自我概念,以下是施測結果,請計算信度。PersonABCDEFGHIJ
4、Form A161214109111391612Form B1512151010121491613做法與再測信度相同,請參照。Correlations紙筆計算結果:PersonABCDEFGHIJForm A16121410911139161212.22.4413Form B151215101012149161312.62.289XA XB2401442101009013218281256156XAXB=1591N=106題的隨堂測驗施測5位學生, Y表示答對,N表示答錯,以下是測驗結果,請計算信度。PersonItem 1Item 2Item 3Item 4Item 5Item 6JoeYY
5、YYNYSamYNNYNYSueYYNYYYPegNYNNYNGilNYNNYY【參】 折半信度(Split-half Reliability)步驟一 輸入資料步驟二 轉換資料為數字按【Transform】【Recode】【Into Same Variables】出現下面的對話框後將左邊方格內item1item6選至右邊String Variables內後點選鍵出現下列對話框後,將”N”定義為”0”,將”Y”定義為”1”後按鍵之後便會將資料轉換成下面的數字步驟三 將string的屬性改為numeric步驟四 計算奇數題與偶數題的和按【Transform】【Compute】即出現下面的對話框(此
6、為奇數題的範例,偶數題亦然)結束後便會在spss Data Editor對話框中出現奇數題和偶數題的和步驟四 執行BivariateCorrelations紙筆計算結果. 計算兩個”半測驗”的相關StudentJoeSamSuePegGilOdds212111.4.4899Evens323122.2.7483X1X262612X1X2 =17N=5 校正相關係數為折半信度Spearmen-Brown prophesy formula 史比校正公式 (當兩個半測驗變異數相等時使用)Guttman prophesy formula 哥德曼校正公式 (當兩個半測驗變異數不等時使用)*折半信度* 折半
7、信度也可直接使用SPSS計算 步驟一 輸入資料步驟二 按【Analyze】【Scale】【Reliability Analysis】將左邊方格內的變項依所需次序分前後半選入右邊items的方格內,在左下角的Model框中選取Split-half後按鍵,再按。Reliability* Method 1 (space saver) will be used for this analysis * R E L I A B I L I T Y A N A L Y S I S - S C A L E (S P L I T)Reliability CoefficientsN of Cases = 5.0
8、N of Items = 6Correlation between forms = .8729 Equal-length Spearman-Brown = .9321Guttman Split-half = .8889 Unequal-length Spearman-Brown = .9321 3 Items in part 1 3 Items in part 2Alpha for part 1 = -2.5000 Alpha for part 2 = .0000標準的折半信度算法:先求各題的難度,再依難度加以排序,再施行上述的方法透過平均值可看出其難度平均高的難度低 平均低的難度高排序由難度
9、低到高2 6 1 4 5 3,在丟入變項時依單偶分為:2 1 5、6 4 3兩組,排列數據時前後排列。CorrelationsCorrelations* Method 1 (space saver) will be used for this analysis * R E L I A B I L I T Y A N A L Y S I S - S C A L E (S P L I T)Reliability CoefficientsN of Cases = 5.0 N of Items = 6Correlation between forms = .0000 Equal-length Spea
10、rman-Brown = .0000Guttman Split-half = .0000 Unequal-length Spearman-Brown = .0000Note # 11999The correlation between forms (halves) of the test is negative. Thisviolates reliability model assumptions. Statistics which are functions ofthis value may have estimates outside theoretically possible rang
11、es. 3 Items in part 1 3 Items in part 2Alpha for part 1 = -.9000 Alpha for part 2 = .6923【肆】 內部一致性(Internal Consistency Coefficient)【計算係數】有5題問答題的隨測驗施測5名學生,每題問答題配分是5分,以下是施測結果,請計算信度。personItem 1Item 2Item 3Item 4Item 5Joe34435Sam43433Sue23323Peg44534Gil32433Dot32323步驟一 輸入資料步驟二 按【Analyze】【Scale】【Reliab
12、ility Analysis】將左邊方格內的變項全選入右邊items的方格內,在左下角的Model框中選取Alpha後按鍵。步驟三 出現下列對話框候選取下列勾選處,後按鍵按。Reliability* Method 2 (covariance matrix) will be used for this analysis * R E L I A B I L I T Y A N A L Y S I S - S C A L E (A L P H A) Correlation Matrix ITEM_1 ITEM_2 ITEM_3 ITEM_4 ITEM_5ITEM_1 1.0000ITEM_2 .2970 1.00