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1、C语言上机考试编程题答案求1+2+3+.+100。（循环）答案#includevoid main() int i,sum=0; for(i=1;i=100;i+) sum=sum+i; printf(%d,sum);2、 求1*2*3*.*10。（循环）答案void main()int i=0,j=1;for (i=2;i=10;i+)j*=i;printf(%d,j);return 0;3、 输入三个数字，输出他们的最大值。（if）答案#includevoid main()int a,b,c,d;scanf(%d,%d,%d,&a,&b,&c);d=max(a,b,c);printf(max
2、=%d,d);getch();/*暂停看运行结果*/int max(int x,int y,int z)int u;if(x=y&x=z)u=x;else if(y=x&y=z)u=y;elseu=z;return(u);4.用起泡法对十个数据排序（数组实现）答案#includemain ( ) int i,j,t; static int a10=5,7,4,2,3,6,1,0,9,8; for(j=0;j9;j+) for(i=0;iai+1) t=ai;ai=ai+1;ai+1=t ; for(i=0;i10;i+) printf(%2d,ai);5、输入十个数字，逆序输出。（数组实现）答
3、案#includemain()int a10,i=0;for(i=0;i=0;i-)printf(%f,ai);6输入两个数，交换他们的值并输出。(元素交换)答案#includeint main () int m,n,temp; scanf(%d%d,&m,&n); if (mn) temp=m; m=n; n=temp; printf(%d,m); return 0;7.输出9*9乘法表。（双层循环)答案#include void main()int i=1;for(i; i=9; i+) int j=1; for(j;j=i;j+) printf(%d*%d=%d , i, j, i*j)
4、; printf(n);8.输入一行字符，将所有的小写字母转换成大写字母，大写字母转换成小写字母，其余字符不变。输出转变后的这行字符。答案#include stdio.hvoid main() char an; int i; scanf(%s,a); printf(大写为：); for(i=0;i=n;i+) if(ai=a) ai=ai-32; printf(%c,ai); printf(n小写为：); for(i=0;i=65&c=97&c=48&c=100&x1000) a=0.01*x;b=10*(0.01*x-a);c=x-100*a-10*b;if(x=(pow(a,3)+pow(
5、b,3)+pow(c,3) printf(%5d,x);x+;6.7main()int m,i,j,s;for(m=6;m10000;m+)s=1;for(i=2;im;i+)if(m%i=0) s=s+i;if(m-s=0)printf(%5d its fastors are 1 ,m);for(j=2;jm;j+) if(m%j=0)printf(%d ,j);printf(n);或main()int m,i,j,s;for(m=6;m1000;m+)s=m-1;for(i=2;im;i+)if(m%i=0) s=s-i;if(s=0)printf(%5d its fastors are
6、1 ,m);for(j=2;jm;j+) if(m%j=0)printf(%d ,j);printf(n);6.8main()int i=1,n;double t,x=1,y=2,s,sum=0;scanf(%ld,&n);while(i=n) s=y/x;sum=sum+s;t=y;y=y+x;x=t;i+;printf(%fn,sum);11，P128 例6.10（译码）#includevoid main()char c;while(c=getchar()!=n)c=c+4;if(cZ+4|cz)c=c-26;printf(%c,c);printf(n);12，P111 5.5 5.6（s
7、witch）5.5#include main()int x,y;printf(输入x：);scanf(%d,&x);if(x1) y=x;printf(x=%3d, y=x=%dn,x,y);else if (x10) y=2*x-1;printf(x=%3d, y=2*x-1=%dn,x,y);else y=3*x-11;printf(x=%3d, y=3*x-11=%dn,x,y);5.6#include main() float score;char grade;case 2:printf(请输入学生成绩：);scanf(%f,&score);while(score100|(score0
8、) printf(n输入有误,请重新输入：);scanf(%f,&score);switch(int)(score/10) case 10:case 9: grade=A;break;case 8: grade=B;break;case 7: grade=C;break;case 6: grade=D;break;case 5:case 4:case 3:case 1:case 0: grade=E;printf(成绩是%5.1f，相应的等级是%c。n,score,grade); 13，P108 例5.5(一元二次方程求根) 例5.6（求闰年）5.5#includevoid main()int
9、 year,leap;scanf(%d,&year);if(year%4=0)if(year%100=0)if(year%400=0)leap=1;elseleap=0;elseleap=1;elseleap=0;if(leap)printf(%d is,year);elseprintf(%d is not,year);printf(a leap year.n)5.614，P31 例2.17 例2.182.17输出50个学生中成绩高于80分者的学号和成绩2.18输出20002500年每一年是否闰年#include void main() int year; year=2000; go: if(year%4 = 0)&(year%100 != 0) | (year%400 = 0) printf(%d is run nian,year); if(year2500) goto end; goto go; end: getch(); 1
