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1、chengC+程序设计模拟题三、用C卄语言描述以下命题1、A小于E并且A大于C2、A和E中有一个小于C3、A是奇数4、E和C中较大者与A相等5、年份Y是闰年四、写出以下程序的执行结果1.#include void main()mt b35=ll,12,1345,21,22,23,24,25,3I,32,33、34,35;mt (*p)5;p=b;fbr(int j=Oj5j+)cout*(*p+j) T ;coutendl;2# mcludevoid swapl(mt a,int b)int temp=a:a=b;b=temp;void swap2(int*a,int*b)int temp=*
2、a;*a=*b,*b=temp;void swap3(int*a,int*b)int*temp=a:a=b.b=temp;void swap4(int &a,int &b)chengint temp=a; a=b; b=temp;void niam()int a=10,b=20;swapl(久 b);coutan: Hbendl;swap2( &a,&b);coutan: Hbendl;swap3(&a,&b);coutan: Hbendl; swap4(a.b);coutan: Hbendl;3. &#iiicludevoid prmt(iiit w)int i;if(w!=0)fb(i=;
3、i=w;i+) coutw;coutendl;void main()pnnt(4);4.# iiiclude#define sw(x,y) xA=y;y/x=x;xA=y; void main()int a=10,b=01;sw(a,b);couta,7rb;5假定输入10个整数：32, 64, 53, 87, 54, 32, 98, 56, 98, 83.以下程序的输出结果是什么？ &# iiicludevoid main()int a、b,c,x;a=b=c=0;for (mt k=0; k10; k+)cinx;switch(x%3)case 0:a+=x; break;case l:b
4、+=x; break;case 2:c+=x; break;coutan ,bM Hcendl;6. *# iiicludevoid main()intj,k;for(j=5；j0;j-)for (k=y; k0; k-)coutH*H;coutendl;7.#include void main()int nNumber;int *pPointer;nNumber = 15;pPointer = & nNumber;coutMnNumber is equal to : nNumberendl:*pPoiiiter = 25;coutMnNumber is equal to : iiNumber
5、endl;8#include iiit *pPouiter;void SomeFunction()pPomter = new int;*pPomter = 25;void main()SomeFunctionQ;coutHValue of *pPointer: H*pPointerendl;delete pPomter;9.#include void AddFive(iiit* Number)*Number = *Number + 5;void main()mt iiMvNumber = 18;coutHMy oiigiiial number is MiiMvNumberendl;AddFiv
6、e(&nMyNumber);coutHMy new number is niiMyNumberendl;10.#include void main()mt Airay3;AiravO = 10;Airavl = 20;Airav2 = 30;int *pAiray；p Array = & Anay0;coutllpArray points to the value. Hendl; cout*pAirayendl;cout*(pAnay+1 产 endl;11. *# mcludeiiit i=4;void main()coutHi=Hiendl;】=5；int i;1=7；cout,i=ien
7、dl;coutHi=Hi;12. *#iiicludevoid fun();void main()fim()；fim()；void fun()static int a=l;iiit i=5;i+;cout,i=,i,a=,aendl;13. & #include class Pointpublic:Pomt(int xx=0, int yy=0) X=xx; Y=yv; countP+； Pomt(Point &p);int GetX() return X;int GetY() return Y;void GetC() coutM Object id=l,coimtPendl; private
8、:mt X,Y;static mt countP;Pomt:Pouit(Pomt &p) X=p.X;Y=p.Y;countP+;iiit Point: :countP=0;void main () Point A(4,5);coutMPoint A；*A.GetX ( ) H/A.GetY ();A. GetC ();Pomt B(A);coutMPoint B；fB.GetX ( ) H；,B.GetY ();B. GetC ();14. *#include mt addDefault(int x=ljnt v=2);void fiin(void);void main(void)int a
9、ddDefault(iiit x=3.iiit y=4);coutaddDefault()endl;firn.;mt addDefault(int x. int y)coutxH+Hyn=H;retuin x+y;void fiin(void)coutaddDefault()endl;15. *#iiiclude void niainQmt m,n.a=3 .b=3 .number; numbei-237; m=number/5;n=ni】mber%5; cout,m=nmendl: coutMn=Mnendl;a+=m;b*=n;coutHa=Maendl; coutHb=Mbendl;16
10、. *#iiiclude void niainQmt width,heightjesult 1 ,iesult2,iesult3; height=3 ;width=5;result l=height3 & width=5; result2=height3 |j width=5;result3=! (width=5); coutresult 1 ,fresult 1 endl; coutresult2Hresult2endl; coutresult3Hresult3endl;17. *#iiiclude void niainQ int i=32,j=6;double df: dfM/j+2.3;
11、 coutHdf=Mdfendl;i=df3;coutni=Hiendl;18. &# mclude mtc10;void add(iiit x,int y)static iiit i=0;ci=x+y;i+;void main()mt a10= 1,2,3,4,5,6,7,8,9,10;int b10= 10,9,8,7,6,5,4,3,2,1;mt i=0,k=0;fbr(i=0;i10;i-H-)add(ai,bi);fbr(i=0;i10;i-H-)coutciM ；19.#mclude void main()char s30=ncomputeimouse,keyH;mt i=0,k=
12、0;coutsendl;while(si!=f0,)if(si=m)通过数组名和下标引用数组元素k+;i+;couti=Hiendl;coutnk=nkendl;20.#iiiclude void niainQchar s=HC+ piogramM;chai- *psl=HcomputerH;chai *ps2,*ps3=s;ps2=MmouseH;coutsH Hps 1M Hps2, Hps3 endl;psl+;ps2+=2;ps3+=4;couts+4n Hps 1M nps2n Hps3endl;cout*sM M*psln ,r*ps2M,*ps3endl;psl=s;19. 如果输入的数据是24和18,那么卞列程序的输出结果是什么？ *材#include iiitc.iiit d)lilt 1;r=c%d;while(r!=O)c=d;d=r；r=c%d;return d;void main()int mge.d;coutMm n=H;ciiimn
