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1、层次分析法各权重计算的 MATLAB程序 clcclear %修改对比矩阵、一致性检验就可以a=1,1,1,4,1,1/21,1,2,4,1,1/21,1/2,1,5,3,1/21/4,1/4,1/5,1,1/3,1/31,1,1/3,3,1,12,2,2,3,3,1;x,y=eig(a);eigenvalue=diag(y);lamda=eigenvalue(1);ci1=(lamda-6)/5;cr1=ci1/w1=x(:,1)/sum(x(:,1)b1=1,1/4,1/2;4,1,3;2,1/3,1;x,y=eig(b1);eigenvalue=diag(y);lamda=eigenva
2、lue(1);ci21=(lamda-3)/2;cr21=ci21/w21=x(:,1)/sum(x(:,1)b2=1 1/4 1/5;4 1 1/2;5 2 1;x,y=eig(b2);eigenvalue=diag(y);lamda=eigenvalue(1);ci22=(lamda-3)/2;cr22=ci22/w22=x(:,1)/sum(x(:,1)b3=1 3 1/3;1/3 1 1/7;3 7 1;x,y=eig(b3);eigenvalue=diag(y);lamda=eigenvalue(1);ci23=(lamda-3)/2;cr23=ci23/w23=x(:,1)/sum
3、(x(:,1)b4=1 1/3 5;3 1 7;1/5 1/7 1;x,y=eig(b4);eigenvalue=diag(y);lamda=eigenvalue(1);ci24=(lamda-3)/2;cr24=ci24/w24=x(:,1)/sum(x(:,1)b5=1 1 7;1 1 7;1/7 1/7 1;x,y=eig(b5);eigenvalue=diag(y);lamda=eigenvalue(2);ci25=(lamda-3)/2;cr25=ci25/w25=x(:,2)/sum(x(:,2)b6=1 7 9;1/7 1 1 ;1/9 1 1;x,y=eig(b6);eigenvalue=diag(y);lamda=eigenvalue(1);ci26=(lamda-3)/2;cr26=ci26/w26=x(:,1)/sum(x(:,1)w_sum=w21,w22,w23,w24,w25,w26*w1ci=ci21,ci22,ci23,ci24,ci25,ci26;cr=ci*w1/sum*w1)