《02运算符、表达式、流程控制(精品)》由会员分享，可在线阅读，更多相关《02运算符、表达式、流程控制(精品)（5页珍藏版）》请在金锄头文库上搜索。
1、1、 完成5!的计算 package com.softeem.HomeWork;/* * 阶乘 */public class Multiply public static void main(String args)int i ;int j =1; for(i=1;i=5;i+)j = j*i;System.out.println(结果=+j);2、统计int a = 847574中位值为”1”的个数package com.softeem.HomeWork;/* * 统计已知数子二进制表示时的1的个数 * author Administrator * */public class Static
2、lice public static void main(String args)int a =847574;int c = 0;while( a!=1 )if(a%2=1)c+;a=a/2;System.out.println(c+1);3、在屏幕上打印1-30个数，每7个数换行package com.softeem.HomeWork;/* * 输出三十个数，七个数一行打印出来 * author Administrator * */public class Count public static void main(String args) int j=0;for(int i=1;i=30;
3、i+)System.out.print( +i);j+;if(j=7)System.out.println();j=0;4、打印1000以内的所有素数package com.softeem.HomeWork;/* * 实现在控制台输出1000以内的素数 * author Administrator * */public class Prime public static void main(String args)int t=0;int i=2; System.out.print( +i); for(i=3; i=1000; i+) boolean f = true; for(int j=2;
4、ji;j+) if(i%j=0) f=false; break; if(f) System.out.print( +i);t+;if(t=10)System.out.println();t=0; 5、打印10以内所有的偶数package com.softeem.HomeWork;/* * 输出一到十之间的偶数 * author Administrator * */public class EvenNumber public static void main(String args)System.out.print(1到10之间偶数为 ：);for(int i=1;i=10;i+)if(i%2=
5、0)System.out.print(i+ );6、九九乘法口诀表package com.softeem.HomeWork;/* * 打印输出乘法口诀表 * author Administrator * */public class KouJue public static void main(String args)int i;int j;int z;for(i=1;i=9;i+)for(j=1;j=0&input=10&input=100&input=999)tf.do100_999();elseSystem.out.println(超出取值范围);8、写一个程序，打印出从1加到100的和
6、。(至少两种方式)package com.softeem.HomeWork;public class Sum public void add()int i = 1;int sum = 0; while(i=100)sum = sum +i;i+;System.out.println(一到一百的和值为 sum1 = +sum);public static void main(String args)Sum s = new Sum();s.add();/方法二：int sum = 0;for(int i=1;i=100;i+)sum = sum + i;System.out.println(一到一
7、百的和值为 sum2 = +sum);9、写一个判断闰年的程序，要求根据一个年份，显示出Yes或No。package com.softeem.HomeWork;import java.util.Scanner;/* *判断一个输入的年份是否闰年，是就输出Yes，不是就输出No * author Administrator * */public class LeapYear public void leap(int year)int a = year%4;int b = year%100;int c = year%400;if(a=0 & b!=0) |c=0)System.out.print(
8、 +Yes);elseSystem.out.println( +No); public static void main(String args) Scanner scan = new Scanner(System.in); System.out.print(请输入一个年份：); int year = scan.nextInt(); LeapYear ly = new LeapYear(); System.out.print(是否闰年？ ); ly.leap(year); 10、写一个程序，打印出从1000到2009年之间的闰年。package com.softeem.HomeWork;/*
9、* 打印1000到2009之间的闰年* author Administrator * */public class PrintYear public int judage(int year, int count) int div4 = year % 4;int div100 = year % 100;int div400 = year % 400;if (div4 = 0 & div100 != 0) | div400 = 0) System.out.print(year + );count+;return count;public static void main(String args)
10、PrintYear py = new PrintYear();System.out.println(1000到2009中的闰年有:);int count = 0;for (int year = 1000; year = 2009; year+) count = py.judage(year, count);if (count = 10) System.out.println();count = 0;11、从控制台输出,方法定义如右下图：123456234561345612456123561234612345package com.softeem.HomeWork;public class Athwart public static void main(String args)int count = 0;for(int i = 1;i=6;i+)for(int j = i;j=6;j+)System.out.print(j);count+;if(count!=6)int b = 1;doSystem.out.print(b);count+;b+;while(count!=6)
