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1、中级数据库系统工程师上午试题模拟12单项选择题1、 一般来说，软件开发环境都具有层次式的结构， (1) 不是其中的一个层次结构。A. 宿主层 B. 核心层 C. 用户层 D. 应用层 The Simple Network Management Protocol (SNMP)is an 2 protocol that facilitates the exchange of management information between 3 . It is part of the Transmission Control Protocol/Internet Protocol(TCP/IP) prot
2、ocol suite. SNMP enables network 4 to manage network performance, find and sole network problems, and plan for 5 An SNMP -managed network consists of three key components: managed devices , 6 ,and network -management systems .2、A. Physical Layer B. Link Layer C. Network Layer D. Transport Layer3、A.
3、network stations B. network clients C. network devices D. network servers4、A. servers B. administrators C. computers D. routers5、A. network growth B. network structure C. network architecture D. network servers6、A. administrators B. agents C. managers D. servers 计算机的使用方式有如下的 7 方式。其中， 8 方式是把一批数据集中起来，
4、通过通信线路传送到计算中心，由批处理程序加以处理。 批处理 远程批处理 双机 实时 分时 网络7、A. B. C. D. 8、A. 远程批处理 B. 批处理 C. 双机 D. 分时 Object-oriented analysis (OOA. is a semiformal specification technique for the object-oriented paradigm. Object-oriented analysis consists of three steps. The first step is 9 . It determines how the various re
5、sults are computed by the product and presents this information in the form of a 10 . and associated scenarios. The second is 11 , which determines the classes and their attributes; Then determine the interrelationships and interaction among the classes. The last step is 12 , which determines the ac
6、tions performed by or to each class or subclass and presents this information in the form of 13 .9、 A. use-case modeling B. class modeling C. dynamic modeling D. behavioral modeling10、 A. collaboration diagram B. sequence diagram C. use-case diagram D. activity diagram11、 A. use-case modeling B. cla
7、ss modeling C. dynamic modeling D. behavioral modeling12、 A. use-case modeling B. class modeling C. dynamic modeling D. behavioral modeling13、 A. activity diagram B. component diagram C. sequence diagram D. state diagram某进程有5个页面，页号为04，页面变换表如下所示。表中状态位等于0和1分别表示页面“不在内存”和“在内存”。若系统给该进程分配了3个存储块，当访问的页面3不在内
8、存时，应该淘汰表中页号为 14 的页面。假定页面大小为4K，逻辑地址为十六进制2C25H，该地址经过变换后，其物理地址应为卜六进制 15 。 页号页帧号状态位访问位修改位0311010002411130004111114、A0 B1 C2 D415、A2C25H B4096H C4C25H D8C25H 数据模型的三要素指 16 ；其中 17 是对数据系统的静态特性的描述， 18 是对数据库系统的动态特性的描述。16、A.数据类型，数据值，数据操作B.数据类型，数据值，数据结构C.数据结构，数据操作，数据完整性约束 D.数据类型，数据结构，数据完整性约束17、A. 数据值 B. 数据类型 C.
9、 数据结构 D. 数据操作18、A. 数据值 B. 数据类型 C. 数据结构 D. 数据操作19、现有四个作业，它们提交、运行情况如下表，若采用先来先服务(FCFS)算法进行作业调度，则其平均周转时间为 (19) 。作业提交时间运行时间153.0266.5374.5482.0 A. 4.0 B. 6.875 C. 9.125 D. 10.0 As mentioned above, C imposes relatively few built - in ways of doing things on the programmer. Some common tasks, such as manip
10、ulating 20 , 21 , and doing 22 (I/O), are performed by calling on library functions. Other tasks which you might want to do, such as creating or listing directories, or interacting with a mouse, or displaying windows or other 23 elements, or doing color graphics, are not defined by the C language at
11、 all. You can do these things from a C program, of course, but you will be calling on services which are peculiar to your programming environment 24 , processor, and operating system) and which are not defined by the C standard. Since this course is about portable C programming, it will also be stee
12、ring clear of facilities not provided in all C environments.20、A. lines B. strings C. threads D. routes21、A. allocating storage B. allocating memory C. distributing memory D. assigning storage22、A. input/output B. inoptimization/optimization C. inside/outside D. inordinacy/ordinance23、A. user - inte
13、rconnect B. person - interconnect C. user - interface D. person - interface24、A. gatherer B. translator C. generator D. compiler25、在以下有关经营性性互联网和公益性互联网的说法中不正确的是 (25) 。 A. 经营性互联网络应当享受同等的资费政策 B. 经营性互联网络应当享受同等的技术支撑条件 C. 公益性互联网络是指为社会提供公益服务的，不以盈利为目的的互联网络 D. 公益性互联网络所使用信道的资费不能享受优惠政策26、若某一组数进栈的序列为123456，则该组数的出栈序列 (26) 是436512； (26) 是132465。 A. 可能 可能 B. 可能 不可能 C. 不可能 可能 D. 不可能 不可能27、 多形病毒指的是 (27) 的计算机病毒。 A可在反病毒检测时隐藏自己 B每次感染都会改变自己 C可以通过不同的渠道进行传播 D可以根据不同环境造成不同破坏28、已知有关系“STUDENT”，则关系运算ANE80(STUDENT)用SQL语句表示为 (28) 。 A. SELECT( * )FROM STUDEN
