《chemical-reaction-engineering-3ed-edition作者-octave-levenspiel-课后习题答案》由会员分享，可在线阅读，更多相关《chemical-reaction-engineering-3ed-edition作者-octave-levenspiel-课后习题答案（44页珍藏版）》请在金锄头文库上搜索。
1、 Corresponding Solutions for Chemical Reaction Engineering CHAPTER 1 OVERVIEW OF CHEMICAL REACTION ENGINEERING1 CHAPTER 2 KINETICS OF HOMOGENEOUS REACTIONS.3 CHAPTER 3 INTERPRETATION OF BATCH REACTOR DATA7 CHAPTER 4 INTRODUCTION TO REACTOR DESIGN.19 CHAPTER 5 IDEAL REACTOR FOR A SINGLE REACTOR.22 CH
2、APTER 6 DESIGN FOR SINGLE REACTIONS .26 CHAPTER 10 CHOOSING THE RIGHT KIND OF REACTOR 32 CHAPTER 11 BASICS OF NON-IDEAL FLOW.34 CHAPTER 18 SOLID CATALYZED REACTIONS43 1 Chapter 1 Overview of Chemical Reaction Engineering 1.1 Municipal waste water treatment plant. Consider a municipal water treatment
3、 plant for a small community (Fig.P1.1). Waste water, 32000 m3/day, flows through the treatment plant with a mean residence time of 8 hr, air is bubbled through the tanks, and microbes in the tank attack and break down the organic material (organic waste) +O2 CO2 + H2Omicrobes A typical entering fee
4、d has a BOD (biological oxygen demand) of 200 mg O2/liter, while the effluent has a megligible BOD. Find the rate of reaction, or decrease in BOD in the treatment tanks. Waste water 32,000 m3/day Waste water Treatment plant Clean water 32,000 m3/day 200 mg O2 needed/liter Mean residence time =8 hr t
5、 Zero O2 needed Figure P1.1 Solution: )/(1017 . 2 )/(75.18 3 1 32 / 1000 1000 1 )0200()( 3 1 32000 3 1 32000 1 343 3 3 3 smmoldaymmol day mol g m L mg g L mg day day m day day m Vdt dN r A A 1.2 Coal burning electrical power station. Large central power stations (about 1000 MW electrical) using flui
6、ding bed combustors may be built some day (see Fig.P1.2). These giants would be fed 240 tons of coal/hr (90% C, 10%H2), 50% of which would burn within the battery of primary fluidized beds, the other 50% elsewhere in the system. One suggested design would use a battery of 10 fluidized beds, each 20
7、m long, 4 m wide, and containing solids to a depth of 1 m. Find the rate of reaction within the beds, based on the oxygen used. 2 Solution: 3 80010) 1420(mV )/(9000101089 . 05 . 010240 33 hrbedmolc hr kgc kgcoal kgc hr coal t Nc )/(25.11 1 9000 800 11 3 2 2 hrmkmolO t N V rr c cO )/(12000 4 12000 19
8、000 2 hrbedmol dt dO )/(17 . 4 800 )/(105 . 11 3 4 2 2 smmol hrbedmol dt dO V rO 3 Chapter 2 Kinetics of Homogeneous Reactions 2.1 A reaction has the stoichiometric equation A + B =2R . What is the order of reaction? Solution: Because we dont know whether it is an elementary reaction or not, we cant
9、 tell the index of the reaction. 2.2Given the reaction 2NO2 + 1/2 O2 = N2O5 , what is the relation between the rates of formation and disappearance of the three reaction components? Solution: 5222 24 ONONO rrr 2.3A reaction with stoichiometric equation 0.5 A + B = R +0.5 S has the following rate exp
10、ression -rA = 2 C0.5 ACB What is the rate expression for this reaction if the stoichiometric equation is written as A + 2B = 2R + S Solution: No change. The stoichiometric equation cant effect the rate equation, so it doesnt change. 2.4 For the enzyme-substrate reaction of Example 2, the rate of dis
11、appearance of substrate is given by -rA = , mol/m3s A 0 6 1760 C EA What are the units of the two constants? Solution: 6 0 3 A A C EAk sm mol r 3 /6mmolCA smmolmmol mmol sm mol k 1 )/)(/( / 33 3 3 2.5 For the complex reaction with stoichiometry A + 3B 2R + S and with second-order rate expression -rA
12、 = k1AB 4 are the reaction rates related as follows: rA= rB= rR? If the rates are not so related, then how are they related? Please account for the sings , + or - . Solution: RBA rrr 2 1 3 1 2.6 A certain reaction has a rate given by -rA = 0.005 C2 A , mol/cm3min If the concentration is to be expres
13、sed in mol/liter and time in hours, what would be the value and units of the rate constant? Solution: min )()( 3 cm mol r hrL mol r AA 2244 3 300005 . 0 106610)( min AAAAA CCrr cm mol mol hrL r AAA AA CC cm mol mol L C cm mol C L mol C 3 3 3 10 )()( 2 4232 103)10(300300)( AAAA CCCr 4 103 k 2.7 For a
14、 gas reaction at 400 K the rate is reported as - = 3.66 p2 A, atm/hr dt dpA (a) What are the units of the rate constant? (b) What is the value of the rate constant for this reaction if the rate equation is expressed as -rA = - = k C2 A , mol/m3s dt dN V A 1 Solution: (a) The unit of the rate constan
15、t is /1 hratm (b) dt dN V r A A 1 Because its a gas reaction occuring at the fined terperatuse, so V=constant, and T=constant, so the equation can be reduced to 5 22 )( 66 . 3 66 . 3 )( 1 RTC RT P RTdt dP RTdt dP VRT V r AA AA A 22 )66 . 3 ( AA kCCRT So we can get that the value of 1 . 12040008205 . 0 66 . 3 66 . 3 RTk 2.9 The pyrolysis of ethane proceeds with an activation energy of about 300 kJ/mol. How much faster the decomposition at 650 than at 500? Solution: 586 . 7 ) 923 1 173 1 ( )10/(314 . 8 /300 ) 11 ( 3 211 2 1 2
