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1、电大C+语言程序设计第1、2、3、4次作业及答案第一次作业一、写出下列每个程序运行后的输出结果1. #includevoid main()int x=5;switch(2*x-3)case 4:printf(%d ,x);case 7:printf(%d ,2*x+1);case 10:printf(%d ,3*x-1);break;default:printf(%s ,defaultn);printf(%sn,switch end.);2. #includevoid main()int i,s=0;for(i=1;i=6;i+)s+=i*i;printf(s=%dn,s);3. #inclu
2、devoid main()int i,s1=0,s2=0;for(i=0;i10;i+)if(i%2)s1+=i;else s2+=i;printf(%d %dn,s1,s2);4. #includevoid main()int n=10,y=1;while(n-)y+;y+;printf(y=%dn,y);5. #includevoid main()int f,f1,f2,i;f1=f2=1;printf(%d %d ,f1,f2);for(i=3;i=10;i+)f=f1+f2;printf(%d ,f);if(i%5=0)printf(n);f1=f2;f2=f;printf(n);6.
3、 #include#includevoid main()int i,n;for(n=2;n=20;n+)int temp=(int)sqrt(n);/sqrt(n)求出n的平方根并取整for(i=2;itemp)printf(%d ,n);printf(n);7. #include#includeconst int M=20;void main()int i,c2,c3,c5;c2=c3=c5=0;for(i=1;i=M;i+)if(i%2=0)c2+;if(i%3=0)c3+;if(i%5=0)c5+;printf(%d %d %dn,c2,c3,c5);8. #include#includ
4、econst int M=20;void main()int i,s;for(i=1,s=0;i5的最小n值。5编写一个主函数，求满足不等式22+42+n21000的最大n值，假定分别用i和s为取偶数值和累加值的变量，并限定使用do循环编程。6编写一个主函数，计算并输出n！的值，其中n值由键盘输入。参考答案：1、答案：#includevoid fun4(char* a,int b)doif(*a=0 & *a=9)b*a-48+;while(*a+);/*void main()char * a=122333444499888;int b10=0;fun4(a,b);for(int i=0;i1
5、0;i+)printf(%d ,bi);*/2、答案：#includeconst int M=2,N=3;double Mean(double aMN, int m,int n )double v=0;for(int i=0;im;i+)for(int j=0;jn;j+)v+=aij;return v/(m*n);/*void main()double a23=1,2,3,4,5,6;printf(%lfn,Mean(a,2,3);*/3、答案：#includeint FF(int a , int n)int mul=1;if(n=1)mul*=a0;else mul=an-1*FF(a,n
6、-1);return mul;/*void main()int a6=1,2,3,4,5,6;printf(%dn,FF(a,6);*/4、答案：#includevoid main()double sum=0;int n=1;while(true)if(sum + 1/(double)n 5)break;elsesum += 1/(double)n;n+;printf(%d, %lfn,n,sum);5、答案：#includevoid main()int s=0,i=2;dos+=i*i;if(s+(i+2)*(i+2)=1000)break;else i+=2;while(true);pri
7、ntf(i=%d,s=%d,i,s);6、答案：#includevoid main()int s=0,n;printf(请输入n的值：);scanf(%d,&n);for(int i=1;i=n;i+)s=s*i;printf(n=%d,s=%d,n,s);第三次作业一、写出下列每个程序运行后的输出结果1 程序代码：#include void SB(char ch) switch(ch) case A: case a:printf(WW ); break;case B: case b:printf(GG ); break;case C: case c:printf(PP ); break;de
8、fault:printf(BB ); break;void main() char a1 = b, a2 = C, a3 = f;SB(a1); SB(a2); SB(a3); SB(A);printf(n);2 程序代码：#include #include double SD(int a, int b, char op) double x;switch(op) case +: x = a + b; break;case -: x = a - b; break;case *: x = a * b; break;case /: if(b) x = (double)a/b; else exit(1
9、); break;default: printf(运算符错！n); exit(1); return x;void main() int x = 20, y = 8;printf(%3.2lf , SD(x, y, -);printf(%3.2lf , SD(x, y, *);printf(%3.2lfn, SD(x + y, y, /);3 程序代码：#include void WF(int x, int y) x = x + y;y = x + y;printf(subs: x, y = %d, %dn, x, y);void main() int x = 18, y = 23;printf(main: x, y = %d, %dn, x, y);WF(x, y);x = 2 * x;printf(main: x, y = %d, %dn, x, y);4 程序代码：#include #include void fun(char ss);void main() char s15 = 567891234;fun(s);printf(%sn, s);void fun(char ss) int i, n = strlen(ss);for(i = 0; i n / 2; i +) char c = ssi;ssi = ssn - 1 - i;ssn - 1 - i
