《具孤立奇点的完全交叉的上同调(》由会员分享，可在线阅读，更多相关《具孤立奇点的完全交叉的上同调(（4页珍藏版）》请在金锄头文库上搜索。
1、?36?6?Vol.36, No. 6 1993x11MACTA MATHEMATICA SINICANov., 1993ielnbasoh?aqrc?p?(?Z?D200433)wvy?z?fg?U?CX?K?V?UXX?f?IV, x V?V?i?1X?IV= fOV, f?bL?M?mHp(V,k,x)EHp?V,x?.?N?P?M?mHp?V,k,x?EHp?V,x? . ?U(k),O U(k)?L?V(k),OV(k)?UEV?kV?oI?jkf = F OU(k)?f OU?TaylorP?V(k)?s?mlY?V,kLV,k,?BFU(k)?d?pV,k= pU,k/fp U,
2、k+ Fp U,k+ DF p1 U,k,pV,k=pU,k/fpU,k+ FpU,k+ df p1U,k+ DF p1U,k.G? V,k: OV(k)DV,k1 pV,kpDp+1V,kp1 ,V,k: OV(k)dV,k1 pV,kpdp+1V,kp1 .?N?CDQk: OV(k) OV(k1),?r?OV-?kp: pV,kppV,kp1Ekp:pV,kppV,kp1?r?OV-?Dkp= kp1D, dkp=kp1d,?kp:Hp? V,k? Hp? V,k1?Lkp:Hp?V,k? Hp ?V,k1? .?s?OV(l),l,? pV,l,l?E?pV,l,l? .?J?OV()
3、=1987?12?17?1993?3?5?840?36?lim lOV(t), pV,= lim lpV,l,pV,= lim lpv,?V,= OV()D1V, p V,Dp+1V, V,= OV()d1V, pV,dp+1V, .?Hk p + q + 2It q N?q,tk= 0.?DQDq,t: q,tk q+1,tk;Dq,pk(q)t2,(q)t1,(q)t1,(q)t)=?(1)t2D(q)t2,S(q,p)t2kpq(q)t2+ (1)t1D(q)t1,(1)t1D(q)t1, S(q,p)t1kpq(q)t1+ (1)tD(q)t?.?ODq+1,tk Dq,tk= 0,
4、q 0, t 0; Dq,t1k q,tk= q+1,tk Dq,tk, q 0, t 1.a?0,tkD0,tk 1,tk q,tkDq,tk q+1,tk ?Z?Ka,b= a,k+2bk,?da,b= Da,k+2bk: Ka,b Ka+1,b,?da,b= (1)aa,k+2bk : Ka,b Ka,b+1.bVT?Z?z?Eb,a 1= pU,xa = 0, b = k + 2,= pU,xa = k p, b = p + 1,?= 0a = 0, k p + 1 b k + 1Ia = k p,0 b p,= 0?.?Ea,k+2 2= Ha? kp pU,x? .hF?t?w?b
5、?M?Ea,k+2 2,?H0? kp pV,x? = pV,x,p N 2,Hq? kp pV,x? = 0,1 q N p 5,kN+4HNp4? kp pV,x? = 0.842?36?H?Kd?z? Ep,02= Hp?V,x?,p N 2,Ep,q2= 0,1 q N p 5,kN+4Ep,Np42= 0.?f?Wq?dk2 x?V?i?IV= fOV,x, f?bLHl?V,x? = Hl(V,x),l N 4.?jtu1?R?Ak?U?(?),?y?12A:2 (1991), 137144.2 Xiao Er Jian, On cohomology of singularities ofCmappings, Math. Ann., 262 (1983), 255272.3?R?Ak?ER?e?29:3 (1986), 385388.
