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1、Shandong steel trawler of 104 gross tonnagePropeller design documentInstructor:xunli liaoStudentname: 吕保达StudentID: u200816943Class: 0803Completion Date:2011/5/261. Main parameters of the hullShip Type: Single Propeller Engines Afterward Steel TrawlerLWL 27.5m Cb 0.502LPP 26.0m Cp 0.592Breadth 5.40m
2、 B/Tm 2.84Depth 2.50m 137.35tAverage Draft 1.90m Xb -0.78mAft Draft 2.40m Zs 0.35mEstimate the hull effective power by the method of AyreSpeed v(kn) 9 10 11Speed length ratio V/L1/2 0.97 1.08 1.19Froude numbers Vs/(gL)1/2 0.290 0.322 0.354 Standard C0 look up the diagram 7-3 295 243 205Standard Cbc
3、look up the table 7-5 0.593 0.56 0.546Real Cb(fatter or thinner) (%) 15.35,thinner 10.36,thinner 8.06,thinnerCbs amendment(%) 11.21 7.174 5.104Cbs amended amount 1 33 17 10Amended Cb 1 328 260 215B/T amendment(%)=-10Cb(B/T-2)% -4.2168 -4.2168 -4.2168amount of B/T amendment,2 -14 -11 -9C2 after Amend
4、ed B/T C2 314 249 206Standard Xc,%L,before or after amidships1.838 After amidships2.327After amidships2.495After amidshipsReal Xc,%L,before or after amidships3,after amidships3,after amidships3,after amidshipsDifference %L,before or after the standard Xc 1.162,after0.6725,after0.5045,afterXcs amendm
5、ent(%)look up the 0.22 0.5 0.96table 7-7(b)amount of Xcs amendment,3 Equation (7-24) -1 -1 -2the C3 after amend Xc 313 248 204Amendment of the length (% )=(Lwl-1.025Lbp )/Lwl*100% 3.2 3.2 3.2Amuont of the amendment of length 4 Equation (7-25) 10 8 7the C4 after amend length 323 256 211Vs3 729 1000 1
6、331Pe= 0.64*Vs3/C4*0.735(KW) 39 68 1092. the Parameters of the enginetype 6160A-123Power(KW) 136MainengineRotational speed(rpm) 850type 2HC250 Gearbox Reduction ratio 1.97:13. Estimation of the promoting factors(1) Wake Fraction This ship is a single screw steel trawler,so we can use Hankexieer form
7、ula to estimate the wake fraction :=0.77Cp-0.28So the wake fraction is 0.176.(2) Thrust Deduction FractionTo the single screw steel trawler ,the thrust deduction fraction t can also be estimated by the Hankexieer formula:t=0.77 Cp-0.30So the thrust deduction fraction t is 0.156(3) Relative Rotative
8、EfficiencyBecause of the lack of data, we approximately value the relative rotative efficiency R 1.0.(4) Hull EfficiencyH =(1-t)/(1-)=(1-0.156)/(1-0.176)=1.024.Number of Blades According to the general conditions, the number of the blades of the single paddle ship is usually 4. Whats more ,we have m
9、ore detailed charts of 4-blade propeller, so, we chose the 4-blade propeller.5 Estimation of the AE/A0 Estimate the AE/A0 by the formula: AE/A0 = (1.3+0.3Z)T / (P0-Pv)D 2 + kAmong this ,in the design speed, PE=71.5KW,V=10.1kn,T=PE/(1-t)V=71.5/(1-0.156)10.10.5144)=16.31kN,When the temperature of the
10、water is 15,the Pv=1.705 kN/m2.The static pressure is P0=Pa+hs=(10330+1025(2.4-0.35)9.8N/m2=121.83kN/m2Value the k 0.2Get the D is 1.5m from the hull lines.So the AE/A0 = (1.3+0.3Z) T / (P0-Pv)D 2 + k=(1.3+0.34)16.31/(121.83-1.705) 1.52)+0.2=0.3516. Introduction to the choice of the impeller At pres
11、ent ,in the designing of the cargo ship, the designers mainly use the B-screw series and the MAU-screw series.Now ,we choose the MAU-screw series.7. Choose two or three charts ,then calculate the maximum speed. Choose the MAU4-40,MAU4-55,MAU4-70 charts.Suppose the reserve power is ten percent of the
12、 rated power, the shaft transmission efficiency S=0.98 and the gear efficiency G=0.96.The power the propeller received is PD0,PD0=Ps0.9SGR=115.14KW=156.67hp8. Go on with the final design with the charts chose in the previous step ,and obtain three groups of parameters of the propeller and the maximu
13、m speed.in which, the rotation speed of the propeller is N=n/i=850/1.97=431.47r/minWith the - charts of the MAU4-40,MAU4-55,MAU4-70,we PBobtain the data in the following table:Item unit numberAssumed speed V kn 9.000 10.000 11.000 VA=(1-)*V kn 7.416 8.240 9.064 Bp=N*PD0.5/VA2.5 36.059 27.709 21.835
14、Bp1/2 6.005 5.264 4.673 70.000 63.000 57.000 P/D 0.680 0.710 0.750 O 0.580 0.615 0.643 MAU4-40PTE=PDO H O hp 93.077 98.693 103.187 68.500 61.000 55.000 P/D 0.720 0.760 0.810 O 0.565 0.595 0.630 MAU4-55PTE=PDO H O hp 90.670 95.484 101.101 67.000 60.400 54.500 P/D 0.730 0.770 0.830 O 0.545 0.575 0.595
15、 MAU4-70PTE=PDO H O hp 87.460 92.274 95.484 With the data in the table, we can draw the following diagram that the PTE, and P/D, 0 are as a function of V at different numbers.We can get the conclusion that the PTE-f(V) function graph intersect with the effective power of the hull at one point. we ca
16、n obtain the designed speed and the best parameters of the propeller such as P/D,D and 0 in the following tableMAU Vmax/kn P/D D/m 04-40 10.1450 0.7152 62.0744 1.4595 0.6192 4-55 10.0720 0.7633 60.5252 1.4129 0.5975 4-70 9.9942 0.7697 60.4363 1.3999 0.5750 9.Cavitation checkObtain the minimum expanded area ratio AE/A0 that is free of cavitation and its maximum speed Vs ,