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1、Solutions_Problems_OM_11e_Stevenson,Chapter 02 - Competitiveness, Strategy, and Productivity,/1 20,4.,*refer to solved problem #2 Multifactor productivity dropped steadily from a high of 3.03 to about 2.84. a.Before: 80 5 = 16 carts per worker per hour. After:84 4 = 21 carts per worker per hour. b.
2、Before: ($10 x 5 = $50) + $40 = $90; hence 80 $90 = .89 carts/$1. After:($10 x 4 = $40) + $50 = $90; hence 84 $90 = .93 carts/$1. c.Labor productivity increased by 31.25%(21-16)/16). Multifactor productivity increased by 4.5%(.93-.89)/.89).,*Machine Productivity Before:80 40 = 2carts/$1.,(1.68-2)/2)
3、,After:84 50 = 1.68 carts/$1. Productivity increased by -16% Chapter 03 - Product and Service Design,Steps for Making Cash Withdrawal from an ATM Insert Card: Magnetic Strip Should be Facing Down Watch Screen for Instructions Select Transaction Options: Deposit Withdrawal Transfer Other Enter Inform
4、ation: PIN Number Select a Transaction and Account Enter Amount of Transaction Deposit/Withdrawal:,Solutions_Problems_OM_11e_Stevenson Depositplace in an envelope (which youll find near or in the ATM) and insert it into the deposit slot Withdrawallift the “Withdrawal Door,” being careful to remove a
5、ll cash 6.Remove card and receipt (which serves as the transaction record) 8.,Chapter 04 - Strategic Capacity Planning for Products and Services,Effective capacity,Actualoutput, 80%,2.Efficiency ,Actual output = .8 (Effective capacity) Effective capacity = .5 (Design capacity) Actual output = (.5)(.
6、8)(Effective capacity) Actual output = (.4)(Design capacity) Actual output = 8 jobs Utilization = .4,Design capacity,Actual output,Utilization ,Effective capacity.4,/2 20,Actualoutput, 8 20 jobs,Design Capacity ,10.a.Given: 10 hrs. or 600 min. of operating time per day. 250 days x 600 min. = 150,000
7、 min. per year operating time.,Solutions_Problems_OM_11e_Stevenson,150,000,150,000,150,000,C,B,A,N 122,000 .81 1 machine,N 208,000 1.38 2 machine,N 186,000 1.24 2 machine,You would have to buy two “A” machines at a total cost of $80,000, or two “B” machines at a total cost of $60,000, or one “C” mac
8、hine at $80,000. b.Total cost for each type of machine: A (2): 186,000 min 60 = 3,100 hrs. x $10 = $31,000 + $80,000 = $111,000 B (2) : 208,000 60 = 3,466.67 hrs. x $11 = $38,133 + $60,000 = $98,133 C(1): 122,000 60 = 2,033.33 hrs. x $12 = $24,400 + $80,000 = $104,400 Buy 2 Bsthese have the lowest t
9、otal cost. Chapter 05 - Process Selection and Facility Layout 3.,Desired output = 4,3 a,Operati7ng time = 56 minutes,5,2 b,4 c,4,CT Od perating time 56 minutes per houer 14 minutes per unit Desired output4 units per hour,9 h,5 i,6,/3 20,Solutions_Problems_OM_11e_Stevenson,a. First rule: most followe
10、rs. Second rule: largest positional weight. Assembly Line Balancing Table(CT = 14),b. First rule: Largest positional weight. Assembly Line Balancing Table,(CT = 14),CT x no. of stations56,Total time45, 80.36%,c.Efficiency ,4.,a,b,d,c /4 20,h,Solutions_Problems_OM_11e_Stevenson a.l. 2. Minimum Ct = 1
11、.3 minutes,.6,N x CT4(1.3), 11.54 percent,3.Idle percent (idle time) ,4.,420 min./day,CT1.3 min./ cycle,Output OT , 323.1 (rounds to 323)copiers / day,N,Total time4.6, 2.3 minutes 2,b. 1.Total time 4.6, CT ,2.Assign a, b, c, d, and e to station 1: 2.3 minutes no idle time Assign f, g, and h to stati
12、on 2: 2.3 minutes,OT420,/5 20,CT2.3,3.Output , 182.6 copiers / day,Solutions_Problems_OM_11e_Stevenson 4.,420 min./day,4.6 min./ cycle,Maximum Ct is 4.6. Output , 91.30 copiers / day,7.,Chapter 06 - Work Design and Measurement,Total,4.332,1,48 240, 7.125 min .,1 .20,ST 5.70 x,NT 6(.95) 5.70 min ., .
13、20,A ,b.,/6 20, 67.12 68 observations,Solutions_Problems_OM_11e_Stevenson,c.e = .01 minutes,.01,/7 20, 46.24, round to 47, 2(.034) 2, e , zs 2,n ,Chapter 07- Location Planning and Analysis,Solutions_Problems_OM_11e_Stevenson,/8 20,Hence, the center of gravity is at (5,4) and therefore the optimal lo
14、cation. Chapter 08 - Management of Quality,Solutions_Problems_OM_11e_Stevenson,2 .,The ru,shift. P,n charts seem erhaps worke ain in the afte urring during,s to show a rs are becomi rnoon instead the last few,pattern of error ng fatigued. If of one 20 mi inutes befor,so, perhaps t nute break co e no
15、on and th,e end of the s,4,Chapter 9 - Quality Control,Power off,Person,Lamp,Didnt turn completely on,Not plugged in,Outlet defective,Defective,Missing BurnedLoose out,Lamp fails to light,Other,Cord,Pareto 12,7,6,uld red1uce some errors. Also, errors,Trans.,should aLlsuobebe G = 1; H = 1; J = 6; D =
16、 10; L = 2; A = 4,b.,4.,Master,l,Schedu,Day,Beg.,1,2,345,6,7,eQua,n,Inv. tity,100150,200,Table,Beg. Inv.,1,23,4,5,6,7,Gross requirements,100,150,200,Stapler,Top Assembly,Base Assembly,Cover,Spring,Slide Assembly,Base,Strike Pad,Rubber Pad 2,Slide,Spring,1/220,1/320,Solutions_Problems_OM_11e_Stevenson
