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一,欧拉临界力公式为二,单元截面:箱型200X200X6X6,单元长度10米,定位柱构件,柱顶施加1N的竖向力。三,不同条件下的欧拉临界力公式:(1)两端铰接:=3.14X3.14X206000X29233500/10000X10000 =593755N=593.755KN (2)一端固定,一端自由:=3.14X3.14X206000X29233500/2X2X10000X10000 =148439N=148.439KN(3)一端固定,一端可垂直移动,不可转动:=3.14X3.14X206000X29233500/0.5X0.5X10000X10000 =2375020N=2375.02KN(4)一端固定,一端铰接:=3.14X3.14X206000X29233500/0.7X0.7X10000X10000 =1211745N=1211.745KN(5)一端固定,一端可水平移动,不可转动:=3.14X3.14X206000X29233500/10000X10000 =593755N=593.755KN程序分析结果:(1)(2)(3)(4)(5)