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1、%例题3-1l1=80r1=0.21x1=0.416b=2.74/1000000vn=110S1=15dp0=40.5dps=128vs=10.5i0=3.5sldb=30+12isldc=20+15i%（1）计算参数并作出等值电路rl=0.5*l1*r1xl=0.5*l1*x1bc=2*l1*bdqb=-0.5*bc*vn*vnrt=0.5*dps*vn2/1000/S12xt=0.5*vs*vn2/100/S1dq0=i0*S1/100dp1=2*dp0/1000dq1=2*dq0*is0=dp1+dq1sb=sldb+s0+dqb*isc=sldc%（2)计算由母线A输出的功率dst=(
2、abs(sc)/vn)2*(rt+xt*i) %变压器绕组中的功率损耗为sc1=sc+dsts11=sc1+sbdsl=(abs(s11)/vn)2*(rl+xl*i) %线路中的功率损耗为s1=s11+dslsa=s1+dqb*i %由母线A输出的功率为%（3）计算各节点电压p1=52.54q1=32.1va=117%线路中电压降落的纵分量和横分量分别为：dvl=(p1*rl+q1*xl)/vapvl=(p1*xl-q1*rl)/vavb=sqrt(va-dvl)2+(pvl)2) %b点电压为pc=20.18qc=17.19vcc=11%变压器中电压降落的纵分量和横分量分别为：dvt=(p
3、c*rt+qc*xt)/vbpvt=(pc*xt-qc*rt)/vbvc1=sqrt(vb-dvt)2+(pvt)2) %归算到高压侧的c点电压vc=vc1*vcc/vn %变电所低压母线c的实际电压 l1 =80r1 =0.2100x1 =0.4160b =2.7400e-006vn =110S1 =15dp0 =40.5000dps =128vs =10.5000i0 =3.5000sldb =30.0000 +12.0000isldc =20.0000 +15.0000irl =8.4000xl =16.6400bc =4.3840e-004dqb =-2.6523rt = 3.4418
4、xt =42.3500dq0 = 0.5250dp1 =0.0810dq1 =0 + 1.0500is0 =0.0810 + 1.0500isb =30.0810 +10.3977isc =20.0000 +15.0000idst =0.1778 + 2.1875isc1 =20.1778 +17.1875is11 =50.2588 +27.5852idsl =2.2818 + 4.5201is1 =52.5406 +32.1053isa =52.5406 +29.4530ip1 =52.5400q1 =32.1000va =117dvl =8.3374pvl =5.1677vb =108.7
5、854pc =20.1800qc =17.1900vcc =11dvt =7.3305pvt =7.3122vc1 =101.7180vc =10.1718 %例题3-2s2=0.3+0.2is3=0.5+0.3is4=0.2+0.15iz12=1.2+2.4iz23=1.0+2.0iz24=1.5+3.0ivn=10%(1)求线路始端功率ds23=(abs(s3)2/vn2)*z23ds24=(abs(s4)2/vn2)*z24s23=s3+ds23s24=s4+ds24s112=s23+s24+s2ds12=(abs(s112)/vn)2*z12s12=s112+ds12%（2）求线路各点
6、电压dv12=(real(s12)*real(z12)+imag(s12)*imag(z12)/(1.05*vn)v2=1.05*vn-dv12dv24=(real(s24)*real(z24)+imag(s24)*imag(z24)/v2dv23=(real(s23)*real(z23)+imag(s23)*imag(z23)/v2v3=v2-dv23v4=v2-dv24%（3）根据上述求得的线路各点电压，重新计算各线路的功率损耗和线路始端损耗ds23=(abs(s3)/v3)2*z23ds24=(abs(s4)/v4)2*z24s23=s3+ds23s24=s4+ds24s112=s23+
7、s24+s2ds12=(abs(s112)/v2)2*z12%从而可得线路始端功率s12=s112+ds12s2 =0.3000 + 0.2000is3 =0.5000 + 0.3000is4 =0.2000 + 0.1500iz12 =1.2000 + 2.4000iz23 =1.0000 + 2.0000iz24 =1.5000 + 3.0000ivn =10ds23 =0.0034 + 0.0068ids24 =0.0009 + 0.0019is23 =0.5034 + 0.3068is24 =0.2009 + 0.1519is112 =1.0043 + 0.6587ids12 =0.0
8、173 + 0.0346is12 =1.0216 + 0.6933idv12 =0.2752v2 =10.2248dv24 =0.0740dv23 =0.1092v3 =10.1155v4 =10.1507ds23 =0.0033 + 0.0066ids24 =0.0009 + 0.0018is23 =0.5033 + 0.3066is24 =0.2009 + 0.1518is112 =1.0042 + 0.6585ids12 =0.0166 + 0.0331is12 =1.0208 + 0.6916i %例题3-3vn=10l1=10l2=4l3=3l4=2va=10.5vb=10.4z1=
9、0.17+0.38*iz2=0.45+0.4*i%的线路等值阻抗zl1=10*z1zl2=4*z1zl3=3*z1zl4=2*z2%求C和D点的运算负荷，为sc1=2600+1600*ise=300+160*isd1=600+200*isd2=1600+1000*idsce=(abs(se/1000)/vn)2*zl4*1000sc=sc1+se+dscesd=sd1+sd2%循环功率z11=0.17-0.38*iscc=1000*(va-vb)*vn/(17*z11)sac=(real(sc)*7+imag(sc)*7*i+real(sd)*3+imag(sd)*3*i)/17+sccsbd
10、=(real(sc)*10+imag(sc)*10*i+real(sd)*14+imag(sd)*14*i)/17-sccs1=sac+sbds2=sc+sdsdc=sbd-sd%C点位功率分点，可推测出E点电压最低点，进一步可求得E点电压dsac=(abs(sac/1000)/vn)2*zl1*1000s1ac=sac+dsacdvac=(real(s1ac/1000)*real(zl1)+imag(s1ac/1000)*imag(zl1)/vavc=va-dvacsce=se+dscedvce=(real(sce/1000)*real(zl4)+imag(sce/1000)*imag(zl
11、4)/vcve=vc-dvcevn =10l1 =10l2 =4l3 =3l4 =2va =10.5000vb =10.4000z1 =0.1700 + 0.3800iz2 =0.4500 + 0.4000izl1 =1.7000 + 3.8000izl2 =0.6800 + 1.5200izl3 =0.5100 + 1.1400izl4 =0.9000 + 0.8000isc1 =2.6000e+003 +1.6000e+003ise =3.0000e+002 +1.6000e+002isd1 =6.0000e+002 +2.0000e+002isd2 =1.6000e+003 +1.000
12、0e+003idsce =1.0404 + 0.9248isc =2.9010e+003 +1.7609e+003isd =2.2000e+003 +1.2000e+003iz11 =0.1700 - 0.3800iscc =5.7703e+001 +1.2898e+002isac =1.6405e+003 +1.0658e+003isbd =3.4606e+003 +1.8951e+003is1 =5.1010e+003 +2.9609e+003is2 =5.1010e+003 +2.9609e+003isdc =1.2606e+003 +6.9509e+002idsac =6.5062e+
13、001 +1.4543e+002is1ac =1.7055e+003 +1.2113e+003idvac =0.7145vc =9.7855sce =3.0104e+002 +1.6092e+002idvce =0.0408ve =9.7447 %例题3-4r1=0.27x1=0.423 b1=2.69/1000000r2=r1x2=x1b2=b1r3=0.45x3=0.44b3=2.58/1000000l1=60l2=50l3=40vn=110snb=20ds0b=0.05+0.6*irtb=4.84xtb=63.5snc=10ds0c=0.03+0.35*irtc=11.4xtc=127s
14、ldb=24+18*isldc=12+9*i%（1）计算网络参数及制定等值电路Z1=l1*(r1+x1*i) %线路1 B1=l1*b1dqb1=-B1*vn2/2Z2=l2*(r2+x2*i) %线路2 B2=l2*b2dqb2=-B2*vn2/2Z3=l3*(r3+x3*i) %线路3 B3=l3*b3dqb3=-B3*vn2/2ztb=(rtb+xtb*i)/2 %变电所bdS0b=2*ds0bztc=(rtc+xtc*i)/2 %变电所cdS0c=2*ds0c%（2）计算节点b和c得运算负荷dstb=(abs(sldb)/vn)2*ztbsb=sldb+dstb+dS0b+dqb1*i+dqb3*idstc=(abs(sldc)/vn)2*ztcsc=sldc+dstc+dS0c+dqb3*i+dqb2*i%（3)计算闭式网络的功率分布s1=(sb*(conj(Z2)+conj(Z3)+sc*conj(Z2)/(conj(Z1)+conj(Z2)+conj(Z3)s2=(sc*(
