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1已知集合M0,1,2,Nx|x2a,aM,则集合MN()A0 B0,1C1,2 D0,2解析:选D.由题意知,N0,2,4,故MN0,22(原创题)集合P1,0,1,Qy|ycosx,xR,则PQ()AP BQC1,1 D0,1解析:选A.Qy|1y1,PQ1,0,13设集合Ax|1x2,Bx|xa,若AB,则a的范围是()Aa1 Ba1Ca2 Da2解析:选B.因为Ax|1x2,Bx|xa,若AB,则a1.4若集合Ax|(x1)23x7,xR,则AZ中有_个元素解析:由(x1)23x7得x25x60,Ax|1x6,因此AZ0,1,2,3,4,5,共有6个元素答案:65设集合A5,log2(a3),集合Ba,b,若AB2,则AB_.解析:AB2,log2(a3)2.a1.b2.A5,2,B1,2AB1,2,5答案:1,2,56已知全集UABxN|0x10,A(UB)1,3,5,7,求集合B.解:UABxN|0x100,1,2,3,4,5,6,7,8,9,10,1,3,5,7A,而B中不包含1,3,5,7,用Venn图表示如图B=0,2,4,6,8,9,10- 1 -