【常耕不辍】小升初数学经典奥数试题1

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1、考前高分冲刺:小升初经典奥数试题考前高分冲刺:小升初经典奥数试题及答案 1、In 2004, 16 June falls on a Wednesday. On what day of the week will 16 June fall in2010?2、If half of a number is 30, then three-quarters of that number is_.3、The sum of the digits of the following product 9995554、Three positive integers have a sum of 28. The gre

2、atest possible product that these integers can have is_.5、In what follows, and are different numbers.When 503 is divided by the remainder is 20.When 503 is divided by the remainder is 20.When 493 is divided by x the remainder is_.6、A lady, her brother, her son and her daughter (all related by birth)

3、 played volleyball. The worst players twin (who is one of the four players) and the best player are of opposite sex.The worst player and the best player are of the same age.Who cannot be the worst player(s)?A) brother onlyB) daughter onlyC) son and daughter onlyD) lady and daughter onlyE) lady only7

4、、If you continue the given number pattern, in what row and in whatposition in that row will the number 320 be?1 - row 12 3 - row 24 5 6 - row 37 8 9 10 - row 4The answers are given in the order of row ; position.参考答案:1、Wednesday 2、45 3、27(求数位上上的数字之和)4、28=9+9+10,因此答案为8105、503-20=483 483=3723=2123,因此

5、x =483,因此此题余数是10. 6、D 7、25,201、Did you know? In the decimal number system (base 10) ten different digits, 0 to 9, are used to write all the numbers. In the binary number system (base 2) two different digits are used, i.e. 0 and 1.Which one of the following numbers is not a valid number in theoctal n

6、umber system (base 8)?A) 128 B) 127 C) 126 D) 125 E) 1242、The number of diagonals that can be drawn in a regular polygon withtwenty sides (icosagon) is_.3、If a and b are integers, 10?3=1,152?7=3, and then 379?6 is equal to_.4、Two numbers are in the ratio 2 : 3. When 4 is added to each number the rat

7、io changes to 5 : 7.The sum of the two original numbers is_.5、The greatest number of Mondays which can occur in 45 consecutivedays is_6、Saul plays a video game in which he scores 4 for a hit and lost 6 for a miss. After 20 rounds his score is 30. The number of times he has missed is_.7、Three girls A

8、, B and C run in a 100 m race. When A finishes, B is 10 mbehind A and when B finishes C is 20 m behind B. How far in metres was C from A when A finished?(Lets assume all the athletes run at a constant speed)8、The areas of the faces of a rectangulabox are 84 cm2 , 70 cm2and 30 cm2.The volume of the b

9、ox in cm3 is_.9、You have 3 weights: 1 kg, 3 kg and 9 kg as well as an equal arm balance, as shown. How many different weight objects can you weigh with these three?Remember the weights may be placed on either side参考答案:1、A 考察我们学过的简单的进制问题,显然8进制中没有8出现2、170 找规律,公式为n(n-3)23、1 定义新运算,就是求3796的余数。4、40,16和245

10、、76、57、28米,根据距离比求出速度比,三者的速度比为1:9/10:18/258、420 分解质因数9、13种每道题的答题时间不超过15分钟。【二年级】课内知识:368-199等于多少呢?课外趣题:按数字规律填出下图中空缺的数:【三年级】课内知识:操场上的学生们进行队列表演,他们排成了8行8列的正方形队列,如果去掉一行一列,请问要去掉多少人?还剩多少人?课外趣题:有7个数,它们的平均数是18。去掉一个数后,剩下6个数的平均数是19;再去掉一个数后,剩下5个数的平均数是20。求去掉的两个数的乘积。【四年级】课内知识:(1686+1683+1689+1681+1691+1685+1687+16

11、78)8等于多少?课外趣题:若在等差数列2,5,8,的每相邻两项中间插入三项,使它构成一个新的等差数列,则原数列的第10项,是新数列的第项。【五年级】课内知识:求4018和7257的最大公约数。课外趣题:把一个自然数的各个数位上的数码相加,所得的和若不是一位数,则再把它的各个数位上的数码相加,直到和是一位数为止。将12009这2009个自然数都经过上述方法处理后,所得到的2009个数中,2和3哪个多?【二年级】1.368-199等于多少呢?解答:原式=368-200+1=168+1=1692.按数字规律填出下图中空缺的数:解答:本题的规律为上面两个数的和等于下面两个数的乘积,因此应该填7。【三

12、年级】1.操场上的学生们进行队列表演,他们排成了8行8列的正方形队列,如果去掉一行一列,请问要去掉多少人?还剩多少人?解答:每行每列都有8个人,而这一行一列必有一个人是重复的,所以减少的人数是82-1=15(人),88-15=49(人)2.有7个数,它们的平均数是18。去掉一个数后,剩下6个数的平均数是19;再去掉一个数后,剩下5个数的平均数是20。求去掉的两个数的乘积。解答:第一个去掉的数是187-196=12,第二个去掉的数是196-205=14,这两个数的乘积为1214=168还可以用移多补少的方法:18-(19-18)6=12 19-(20-19)5=14 1214=168【四年级】1

13、.(1686+1683+1689+1681+1691+1685+1687+1678)8解答:原式=(16808+6+3+9+1+11+5+7-2)8=168088+(6+3+9+1+11+5+7-2)8=1680+408=16852.若在等差数列2,5,8,的每相邻两项中间插入三项,使它构成一个新的等差数列,则原数列的第10项,是新数列的第项。解答:在每相邻两项中间插入三项,则原数列的第10项之前共插入了39=27项,故原数列的第10项是新数列的第10+27=37项。【五年级】1.求4018和7257的最大公约数。解答:(7257,4018)=(3239,4018)=(3239,779)=(123,779)=(123,41)=412.把一个自然数的各个数位上的数码相加,所得的和若不是一位数,则再把它的各个数位上的数码相加,直到和是一位数为止。将12009这2009个自然数都经过上述方法处理后,所得到的2009个数中,2和3哪个多?解答:一个数除以9的余数就是它数字和除以9的余数,因此按照题目中的操作办法,每个数最后都会变成它除以 9的余数。连续9个自然数除以9的余数都互不相同,20099=2232,说明这2009个数中除以9余2的有224个,余3的有223个,所以在最后得到的2009个数中,2比3多。5

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