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1、下载可编辑#include #include void main() int arr10=11,4,2,7,3,12,5,34,5,9,i; int s=0; /*found*/ for ( i=0; i10; i+) /*found*/ if (i % 2 = 1) s = s + arri; printf(The result is: %dn, s); 参考答案：#include #include void main() int arr10=11,4,2,7,3,12,5,34,5,9,i; int s=0; /*found*/ for ( i=0;i=9; i+) /*found*/ i
2、f (arri % 2 = 1) s = s + arri; printf(The result is: %dn, s); #include stdio.h#include string.hvoid main( ) char s10; unsigned i;/*found*/1； scanf(%s,s);/*found*/for(i=0;2;i+) n=n*10+si-0; printf(n=%ldn,n);参考答案：#include stdio.h#include string.hvoid main( ) char s10; unsigned i;/*found*/ int n=0; sca
3、nf(%s,s);/*found*/for(i=0;i5;i+) n=n*10+si-0;printf(n=%ldn,n); #include #define N 3 int fun(int aNN) int min; /*begin*/ /*end*/ return min; void main() void NONO( );/函数声明 int aNN=-1,2,3,4,9,5,7,8,6; int i,j,min; printf(array is:n); for(i=0;iN;i+) for(j=0;jN;j+) printf(%5d,aij); printf(n); min=fun(a)
4、; printf(Result is: %dn,min); NONO( ); void NONO( ) FILE *fr,*fw; int i,j,k,m,aNN; fr=fopen(D:exam15400104PROGIN.DAT,r); fw=fopen(D:exam15400104PROGOUT.DAT,w); for(i=1;i=5;i+) for(j=0;jN;j+) for(k=0;kN;k+) fscanf(fr,%d,&ajk); fprintf(fw,%4d,ajk); fprintf(fw,Min = %dn,fun(a); fclose(fr); fclose(fw);
5、参考答案：#include #define N 3 int fun(int aNN) int min; /*begin*/int i,j; min=a00;for(i=0;iN;i+)for(j=0;jaij)min=aij; /*end*/ return min; void main() void NONO( );/函数声明int aNN=-1,2,3,4,9,5,7,8,6; int i,j,min; printf(array is:n); for(i=0;iN;i+) for(j=0;jN;j+) printf(%5d,aij); printf(n); min=fun(a); print
6、f(Result is: %dn,min); NONO( ); void NONO( ) FILE *fr,*fw; int i,j,k,m,aNN; fr=fopen(D:exam15400104PROGIN.DAT,r); fw=fopen(D:exam15400104PROGOUT.DAT,w); for(i=1;i=5;i+) for(j=0;jN;j+) for(k=0;kN;k+) fscanf(fr,%d,&ajk); fprintf(fw,%4d,ajk); fprintf(fw,Min = %dn,fun(a); fclose(fr); fclose(fw); #includ
7、e #include void main() int a33=4,4,34,37,3,12,5,6,5,i,j,max,min; max = min = a00; for ( i=0; i3; i+) /*found*/ for ( j=1; j3; j+) if ( max aij ) max = aij; /*found*/ if (min aij) min = aij; printf(The max is: %dn, max); printf(The min is: %dn, min); 参考答案：#include #include void main() int a33=4,4,34,
8、37,3,12,5,6,5,i,j,max,min; max = min = a00; for ( i=0; i3; i+) /*found*/ for ( j=0; j3; j+) if ( max aij) min = aij; printf(The max is: %dn, max); printf(The min is: %dn, min);#include main() int i,g; for(i=1;i1000;i+) /*found*/ g=_(1)_10; /*found*/ if(_(2)_) printf(%4d,i); printf(n); 参考答案：#include
9、main() int i,g; for(i=1;i1000;i+) /*found*/ / g=_(1)_10; g=i%10; /*found*/ / if(_(2)_) if(i=g*g*g) printf(%4d,i); printf(n); #include stdio.h int fun(int m,int n) /*begin*/ /*end*/ void main() void NONO( );/函数声明 int s; int m,n; printf(Enter m n:n); scanf(%d %d,&m,&n); s=fun(m,n); printf(s=%dn,s); NONO( ); void NONO( ) FILE *fr,*fw; int i,x,y; fr=fopen(D:exam15400116PROGIN.DAT,r); fw=fopen(D:
