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1、地大混凝土结构基本原理在线作业一（The basic principle of concrete structure is one）The basic principle of concrete structure is oneTotal score: 100 test time: -Single topic selection(a total of 25 questions, 100 points.)1. Determine the most unfavorable group of internal forces under the following minor bias:A. Nmax
2、, MmaxB. Nmax, MminC. Nmin, MmaxD. Nmin, MminFull marks: 4 points2. The structure has good working performance under normal load and is called structure ().A. securityB. the applicabilityThe durability of C.D. the reliabilityFull marks: 4 points3. The general board is not used for shear calculation,
3、 mainly because:A. The plates are not equipped with strapsB. The width of the plate is greater than the heightC. Plates are generally subjected to uniform loadD. The shear capacity of the general plate is greater than that of the bent bearing capacityFull marks: 4 points4. () the structural system h
4、as the advantages of flexible structure and convenient use, with large rigidity and strong earthquake resistance, so it is widely used in high-rise office buildings and hotel buildings.A. frameworkB. shear wallC. Frame-shear wallD. Framework - tube bodyFull marks: 4 points5. The component coefficien
5、t of concrete material is ()A. 1.25B. 1.35C. 1.4D. 1.45Full marks: 4 points6. The approximate relationship between the shear bearing capacity of the beam and the shear bearing capacity of the beam is ().A: the bearing capacity of the b0 shearing force of the b0 shearsB. The bearing capacity of slant
6、 failure of , the bearing capacity of the shear failureC. The bearing capacity of shear pressure destroyed by the bearing capacity of D. The bearing capacity of slant failure of , the bearing capacity of the shear failureFull marks: 4 points7. When combining the internal forces of single-storey plan
7、t, the load combination of variable load combined with 0.85 is ().A. Constant load + wind loadB. Live load + wind loadC. constant load + live load + crane loadConstant load + wind load + live loadFull marks: 4 pointsThe formula for calculating the bearing capacity of the cross section of the bending
8、 component is based on ().A. slope failureB. Shear failureC. baroclinic damageD. Oblique bending failureFull marks: 4 points9. In the most unfavorable combination of the single-storey plant, () the components may form small eccentric compression failure.A. + Mmax and its corresponding N, VB. Nmax an
9、d its corresponding M, VC. Vmax and its corresponding M, ND. - Mmax and its corresponding N, VFull marks: 4 points10. The support of the column column under the single-storey workshop is set in the expansion joint section ().A. At both ends, between columns corresponding to the support between colum
10、nsB. In the middle, the corresponding columns are supported horizontallyC. both sides support horizontal horizontal support for the corresponding columnD. In the middle, between columns corresponding to the support between columnsFull marks: 4 points11. The static calculation of the house can be cal
11、culated according to the plane frame or frame of space work which is hinged by the floor (roof) and the wall column.A. elastic schemeB. Just elastic schemesC. rigid schemeD.B and CFull marks: 4 points12. The flexural damage of the single-layer plant column bulls legs occurs more in the () case.A. 0.
12、75B. 0.1C. a/h0 0.1 or lessD. The ratio of tensile longitudinal reinforcement and the band ratio are lowFull marks: 4 points13. () showed significant brittle damage and was not allowed in engineering design and construction.A. small bias damageB. Shear failureC. slope failureD. DamageFull marks: 4 p
13、oints14. The variable load is the total amount of time () that is exceeded during the design reference period, which is referred to as the quasi-permanent value of the variable load.A. ten yearsB. 15 yearsC. 20 yearsD. 25 yearsFull marks: 4 points15. The maximum negative bending distance of one of t
14、he supports of continuous beam, the living load should be arranged.A. The left and right sides are arranged in two straddling arrangementsB. The left and right sides of the pedestal are not arrangedC. The layout should be cross-arranged and arranged in a different wayD. full span arrangementFull mar
15、ks: 4 points16. The following statement is true ().A. A, when the tension point is located in the middle of the two sides of the bar, it is A large deviation memberB. B. The size of eccentricity compression member is the only criterion for the eccentric distanceC. The larger the axial force of the compression member, the smaller the bearing capacity of the oblique sectionD. D. When shea
