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1、第一章1.4指出下列物质在液氨中的酸碱行为（写出反应方程式）：CH3CO2H , NH2CONH2 , CH3CH2OH , NaH1.4 Pointed out that the following substances in acid-base behavior in liquid ammonia(write reaction equation):CH3CO2H , NH2CONH2 , CH3CH2OH , NaH参考答案：CH3CO2H为强酸 CH3COOH+NH3CH3COO-+NH4+ NH2CONH2为弱酸 NH2CONH2+NH3NH4+ +NH2CONH- CH3CH2OH为
2、弱酸 CH3CH2OH+NH3NH4+CH3CH2O- NaH为强碱 NaH+NH3NH2-+H21.4 指出下列物质在液氨中的酸碱行为（写出反应方程式）：1.4 Points out the following material in the soda acid liquid ammonia behavior (write a response equation)CH3COOH,H2NCONH2,CH3CH2OH,NaH解：CH3COOH strong acid CH3COOH+NH3=CH3COO+NH4H2NCONH2 weak acid H2NCONH2+NH3=NH4+NH2CONH
3、CH3CH2OH weak acid CH3CH2OH+NH3=NH4+CH3CH2ONaH strong soda H+NH3=NH2+H21.5指出下列物质在100%H2SO4中的酸碱行为（写出反应方程式）：HNO3 , CH3CO2H , HClO4 , C2H5OH , H2NCONH2 , SO31.5 Pointed out that the following substances in acid-base behavior in 100%H2SO4(write reaction equation):HNO3 , CH3CO2H , HClO4 , C2H5OH , H2NCON
4、H2 , SO3参考答案：HNO3为碱 HNO3 + 2H2SO42HSO4-+NO2+ H3O+ CH3CO2H为碱 CH3COOH + H2SO4HSO4-+ CH3COOH2+ HClO4为酸 HClO4+ H2SO4H3SO4+ CH3COOH2+ C2H5OH为碱 C2H5OH+ 2H2SO4CH3CH2HSO4+ HSO4-+ H3O+ H2NCONH2为碱 H2NCONH2+ H2SO4HSO4-+ H2NCONH3+ SO3为碱 SO3+ H2SO4H2S2O7 H2SO4 +H2S2O7 H3SO4+ HS2O7-1.8 Please write down the chemi
5、cal equation of the following reactions.(1) Potassium amide and aniline have reactions in liquid ammonia.(2) Inject hydrochloric acid into concentrated sulfuric acid and concentrated nitric acid solution to get NO2Cl.(3) Boric acid is dissolved in sulfuric acid.1.9 In liquid ammonia,what is the conc
6、entration of ammonium ion?1.9 in the liquid ammonia, what is the concentration of ammonium ion ?Answer: 2NH3 = NH4 + NH2- K=1.0*10-33NH4 +=K1/2=3.16*10-7 ( MOl/L)1.12 estimate rough the value of PKa about each of theFollowing acids?Answer: 1.phosphite pka1=2 pka2=72. nitric acid pka1=-3 3. Percholor
7、ic acid pka=84. Periodate pka1=2 pka2=71.12 粗略估计下述各酸的pKa值1.12 A rough estimate the following the sour pKa value解：(1)H3PO3 m=1 pK1=2 pK2=pK1+5=7(2)HNO3 m=2 pK=-3(3)HClO4 m=3 pK=-8(4)H5IO6 m=1 pK1=2 pK2=7第二章2.1Determine the following molecules or objects belong point group(1)SiHDBr2 Tetrahedral Cs poi
8、nt group(2)SiFClBrI Tetrahedral C1 point group(3)SiH2Br2 Tetrahedral C2v point group(4)PCl3 Three sides of vertebral C3v point group(5)OPCl3 Three sides of vertebral C3v point group(6)CO2 Linear Dh point group(7)P4O6 Tetrahedral Td point group(8)Mn(CO)5I Octahedral C4v point group(9) Letter T and ZT
9、 C2v point groupZ C2h point group(10)A piece of chalk Cv point group2.1确定下列分子或物体所属的点群（Sure the following molecular or object points of subordinate） 2.3指出下列分子或离子所属的点群，并写出他们所含有的对称元素（Point out the following molecular or ion points of subordinate ,and write out their symmetry element2.8 Which point grou
10、p PtCl42 belong to ? Draw its structure , mark the elements of these operations(each operation mark one).2.9 Known following molecular point group , draw their structures. 2.9 Given the following molecules(ions) belong to which point group,draw their structure.(1)B(OH)3 C3h(2)Cr(en)3 D3(3)Co(gly)3 C
11、3(4)Mn2(CO)10 D4d(5)Allene D2d第三章3.1 Try to estimate the geometries and electronic structures of these following coordinative ions.Co（CN）63（diamagnetism）：octahedron，Oh strong field，low spin， t2g6eg0；NiF64（2 single electron）：octahedron，Oh weak field，high spin， t2g6eg2；CrF64（4 single electron）：octahed
12、ron，Oh weak field，high spin， t2g3eg1；AuCl4（diamagnetism）：plane square，D4h field， eg4a1g2b2g2b1g0；FeCl4（5 single electron）：tetrahedron，Td field， e2t23；NiF62（diamagnetism）：octahedron，Oh strong field，low spin，t2g6 eg0 。1、Describe the structure and electron structure of the following coordination ion.Co
13、(CN)63- (diamagnetism) NiF64- (two unpaired electron)CrF64- (four unpaired electron) AuCl4- (diamagnetism) FeCl4- (five unpaired electron) NiF62- (diamagnetism) 5、Which ones are high-spin state in the following coordination ion. Mn(H2O)2+6 Fe(H2O)3+6 Co(NH3)3+6 Co(H2O)2+6 CoCl2- Fe(CN)4-63.5 The fol
14、lowing cations which are high spin configuration ？(a)Six hydrated manganese ()cation；（b）Six hydrated iron () cation ; (c)Six ammonia cobalt()cation；(d) Six hydrated cobalt()cation ；（e）Four chloride cobalt( II )anion; (f) Six-iron cyanide ()anion.The answer: Water is the weak-field ligands，its splitting can be low，that (a),(b),(d) are high-spin configuration. Cyanide is the strong-field ligands, its splitting can be high, that (f) is low-spin configuration. Amine is a
